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emmainna [20.7K]
3 years ago
13

I need helpp! I’m confused please helpp me

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0
She had a 2/3 chance of picking a green or blue marble
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jarptica [38.1K]
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Zc>Zm
3 0
4 years ago
Thomas finished the 200-meter race in 25. 7 seconds while Mikah finished in 28. 1 seconds. How much faster did Thomas run the ra
kherson [118]

Thomas finished 2.4 seconds faster than Mikah which has higher speed than Mikah.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,

Main body:

200-meter race finished by Thomas =  25.7 sec

200-meter race finished by Mikah = 28.1 sec

The difference between their time shows How much faster did Thomas run the race than Mikah.

=28.1 - 25.7

=2.4 seconds

Hence, Thomas finished 2.4 seconds faster than Mikah which has higher speed than Mikah.

To know more about arithmetic click on The link below

brainly.com/question/14753192

#SPJ1

4 0
1 year ago
Solve the inequality and enter your solution as an inequality.<br><br> X-4&lt;6​
Alex777 [14]

Answer:

x < 10

Step-by-step explanation:

Given: x -4 < 6​

Add four to both sides: x < 10

Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

5 0
2 years ago
PLEASE HELP ME If 0 &lt; z ≤ 90 and sin(9z − 1) = cos(6z + 1), what is the value of z? z = 3 z = 4 z = 5 z = 6
Burka [1]

Answer:

  z = 6

Step-by-step explanation:

We know that ...

  sin(x) = cos(90 -x)

Substituting (9z-1) for x, this is ...

  sin(9z -1) = cos(90 -(9z -1))

But we also are given ...

  sin(9z -1) = cos(6z +1)

Equating the arguments of the cosine function, we have ...

  90 -(9z -1) = 6z +1

  90 = 15z . . . . . . . . . add (9z-1) to both sides

  6 = z . . . . . . . . . . . . divide by 15

_____

<em>Comment on the graph</em>

The attached graph shows 5 solutions in the domain of interest. These come from the fact that the relation we used is actually ...

  sin(x) = cos(90 +360k -x)  . . . . .  for any integer k

Then the above equation becomes ...

  90 +360k = 15z

  6 +24k = z . . . . . . . . . for any integer k

The sine and cosine functions also enjoy the relation ...

  sin(x) = cos(x -90)

  sin(9z -1) = cos(9z -1 -90) = cos(6z +1)

  3z = 92 . . . . . equating arguments of cos( ) and adding 91-6z

  z = 30 2/3

6 0
3 years ago
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