Okay, to find length CE, your going to know the value of <em>x</em>. Length BC + CE = BD + DE.
3x+47+x+26=27+x+10
Simplify the equation to get
4x+73=37+x
you can choose one of four ways to continue, but I will choose to subtract x
3x+73=37
Subtract 73 from both sides of the equal sign
3x=-36
divide by 3 on both sides of the equal sign to get the value of x
x=-12
Now, plug in -12 for x in length CE to get -12+26=14
Step-by-step explanation:
Your previous questions answer is
v=23
w=19
x=22
y=26
z=20
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Answer:
c...........................
divide by I and r so t=p/(ir)
F(x) = 3x^32 + 8x^2 -22x +43
The ends of all the polynomials with even degree behave like quadratic functions.
Given the the coefficient of x^32 is positive, the function opens upwards. Then the two ends go up.