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earnstyle [38]
3 years ago
10

I made a fort for my pet porcupine by connecting two boxes. the first box is 10 meters long, 7 meters wide, and 5 meters high. t

he second box is 4 meters long, 10 meters wide, and 8 meters high. how many cubic meters of space does my porcupine have to play in his fort?
Mathematics
2 answers:
Lerok [7]3 years ago
6 0

First, let's find the volume of the two boxes.

V = lwhV=lwhV, equals, l, w, h

V=10\times7\times5V=10×7×5V, equals, 10, times, 7, times, 5

V= \blue{350} \text{ cubic meters}V=350 cubic metersV, equals, start color blue, 350, end color blue, space, c, u, b, i, c, space, m, e, t, e, r, s

V = lwhV=lwhV, equals, l, w, h

V=4\times10\times8V=4×10×8V, equals, 4, times, 10, times, 8

V= \pink{320} \text{ cubic meters}V=320 cubic metersV, equals, start color pink, 320, end color pink, space, c, u, b, i, c, space, m, e, t, e, r, s

Hint #22 / 3

Since my porcupine can play in both boxes, we need to add the volumes of the two boxes.

\blue{350}+\pink{320}=\green{670}350+320=670start color blue, 350, end color blue, plus, start color pink, 320, end color pink, equals, start color green, 670, end color green

Hint #33 / 3

My porcupine has \green{670}670start color green, 670, end color green cubic meters of space to play in his fort.  

670 is your answer i hoped this help please rate me thanks :)

Furkat [3]3 years ago
5 0

Answer with Step-by-step explanation:

We are given that:

I made a fort for my pet porcupine by connecting two boxes.

The first box is 10 meters long, 7 meters wide, and 5 meters high.

The second box is 4 meters long, 10 meters wide, and 8 meters high.

We have to find how many cubic meters of space  porcupine have to play in his fort.

He can play inside the first box or the second box so, volume of two boxes represents the space porcupine has to play

   =10×7×5+4×8×10

  =  350+320

  = 670

Hence, porcupine can play in 670 cubic meters of space.

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