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3 years ago

Find the next number in the sequence.25, 36, 49, 64, ...

Mathematics

2 answers:

ra1l [238]3 years ago

6 0

Answer:

81

Step-by-step explanation:

25, 36, 49, 64, ...

36 - 25 = 11

49 - 36 = 13 = 11 + 2

64 - 49 = 15 = 13 + 2

64 + 15 + 2 = 81

Vlad [161]3 years ago

4 0

25 to 36 is 11
36 to 49 is 13
49 to 64 is 15
The difference is it’s going up by 2 each time so ...
64 + 17 is 81
The next number is 81

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Answer:

Option B, Option D

Step-by-step explanation:

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3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

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Using an double-angle identity:

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$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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3 years ago

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Serhud [2]

Answer:

Adult = 39

Children = 36

Step-by-step explanation:

The total number of people = 75

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Cost of children ticket = $2.25

Total receipts = $188.25

Let the number of adult = x

Let the number of children = y

X + y = 75 ......equation (i)

(X × 2.75) + (y × 2.25) = 188.25

2.75x + 2.25y = 188.25.......equation (ii)

To find the numbe of adult and children that attended, we'll have to solve equation (i) and (ii) simultaneously.

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Put equation (iii) into equation (ii)

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Collect liketerms

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Answer:

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