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xxTIMURxx [149]
1 year ago
12

F(x)= 2x^3 + 6x^2 -5x - 3, g(x)= 3x-4 find (f-g)(x)

Mathematics
1 answer:
sergeinik [125]1 year ago
8 0

The difference in the given functions is 2x^3 + 6x^2 -8x + 1

<h3>Difference of functions</h3>

Given the following function a shown

f(x)= 2x^3 + 6x^2 -5x - 3

g(x)= 3x-4

Take the difference

(f-g)(x) = f(x) - g(x)

Substitute

(f-g)(x)  = 2x^3 + 6x^2 -5x - 3 - (3x - 4)

Expand

(f-g)(x)  = 2x^3 + 6x^2 -5x - 3 - 3x + 4

(f-g)(x) = 2x^3 + 6x^2 -8x + 1

Hence the difference in the given functions is 2x^3 + 6x^2 -8x + 1

Learn more on polynomials here: brainly.com/question/2833285

#SPJ1

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Using Binomial distribution to determine the probability; we have:

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3 years ago
How much does 12 go into 11
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