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xxTIMURxx [149]
1 year ago
12

F(x)= 2x^3 + 6x^2 -5x - 3, g(x)= 3x-4 find (f-g)(x)

Mathematics
1 answer:
sergeinik [125]1 year ago
8 0

The difference in the given functions is 2x^3 + 6x^2 -8x + 1

<h3>Difference of functions</h3>

Given the following function a shown

f(x)= 2x^3 + 6x^2 -5x - 3

g(x)= 3x-4

Take the difference

(f-g)(x) = f(x) - g(x)

Substitute

(f-g)(x)  = 2x^3 + 6x^2 -5x - 3 - (3x - 4)

Expand

(f-g)(x)  = 2x^3 + 6x^2 -5x - 3 - 3x + 4

(f-g)(x) = 2x^3 + 6x^2 -8x + 1

Hence the difference in the given functions is 2x^3 + 6x^2 -8x + 1

Learn more on polynomials here: brainly.com/question/2833285

#SPJ1

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The volume of a cylinder is 980 pi The height of the cylinder is 20 in. What is the radius of the cylinder?
AlexFokin [52]
█ Question █

The volume of a cylinder is 980 pi The height of the cylinder is 20 in. What is the radius of the cylinder?

█ Explanation <span>█
</span>
We know the volume of the cylinder and the height, too. We are looking to find the radius. Do the following equation that is posted in the screenshot. 

Answer: The radius is 7

<span>Hope that helps! ★ <span>If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia </span></span>

7 0
3 years ago
30 points if you answer this question and please show work !!
worty [1.4K]
I don't know what is between f(x) and g(x), so (for now) there are two posible answers:

1. f(x)g(x) = f(x)\cdot g(x) - function multiplication:

f(x)g(x)=(2x-3)\cdot(3x+8)=2x\cdot3x+2x\cdot8-3\cdot3x-3\cdot8=\\\\=6x^2+16x-9x-24=\boxed{6x^2+7x-24}

2. f(x)g(x)=f(x)\circ g(x) - function composition:

f(x)g(x) = f(x)\circ g(x) = f\big(g(x)\big)=2(3x+8)-3=2\cdot3x+2\cdot8-3=\\\\=6x+16-3=\boxed{6x+13}


5 0
3 years ago
A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.
mario62 [17]

Answer:

(x-7)^2+(y-5)^2=1

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

<u>Center of the circle:</u>

  • The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)

(x_m, y_m) = (7,5)

This is the center coordinate of our circle.

<u>Radius: </u>

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}

r = \sqrt{(6-7)^2+(5-5)^2}

r = \sqrt{1^2}

r = 1

<u>Equation of the circle: </u>

The equation is written as:

(x-a)^2+(y-b)^2=r^2

here, (a,b) are the center points of the circle

in our case this is (a,b)=(x_m,y_m)=(7,5)

and r = 1

(x-7)^2+(y-5)^2=1^2

(x-7)^2+(y-5)^2=1

This is the equation of the circle!

3 0
3 years ago
Customers arrive at a restaurant according to a Poisson distribution at a rate of 20 customers per hour. The restaurant opens fo
jenyasd209 [6]

Answer:

0.087

Step-by-step explanation:

Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:

= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:

X₅ ~ Poisson (20 (5/60))

X₅ ~ Poisson (1.6667)

Formula for computing probabilities for Poisson is as follows:

P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!

P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! =  (e^-1.6667)((1.6667²)/3!)

P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)

P(X₅= 3) = (2.718^(-1.6667))0.46

P(X₅= 3) = 0.1889×0.46

P(X₅= 3) = 0.086894

P(X₅= 3) = 0.087

Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.

8 0
3 years ago
Your friend just purchased a new sports car for $32,000. He received $6,000 for his trade in and he used that money as a down pa
valentinak56 [21]
The solution to the problem is as follows:

let


R = $619.15 periodic payment


i = 0.0676/12 the rate per month


n = 48 periods


S = the future value of an ordinary annuity


S = R[((1 + i)^n - 1)/i]


S = 619.15*[(1 + 0.0676/12)^48 - 1)/(0.0676/12)]


S = $34,015.99

I hope my answer has come to your help. God bless and have a nice day ahead!



5 0
3 years ago
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