First of all we need to formulate two equations.
x = monthly fee per minute
y = monthly fee per minute over 500
500x + 130y = $53.55
500x + 209y = $63.03
Since we know that 500x = $53.55 - 130y we can substitute.
($53.55 - 130y) + 209y = $63.03
79y = 9.48
y = $0.12
Now we can substitute y into the other equation.
500x = $53.55 - 130(0.12)
500x = $53.55 - $15.6
500x = $37.95
So the answer is $37.95 monthly for 500 minutes with an over quota fee of $0.12 per minute.
It would 28 days so it would be 8.4 I think this right hope this helps
Answer:
-7/5.
Step-by-step explanation:
Leave the denominators the same and subtract only the numerators. Since -3 is negative and 4 is a positive being subtracted, you get -7 as the numerator. So, it's -7/5.
Alright first off 8 filters cost $39.92 and out goal is to find the cost of 6 filters Set this up as a proportion. 8 = $39.926 = x
So let find x
x = (6)($39.92) / 8 = $29.94 <span>It costs $29.94 to buy 6 filters.</span>
Answer: b = 1850 - 120w
Step-by-step explanation:
Let w represent the number of weeks for which the books are purchased.
They are being purchased at a steady rate of 120 books per week. This means that the number of books purchased after w weeks would be 120w.
The total number of algebra textbooks that she had initially is 1850
If b represents the number of books left after w-weeks of sales, then the linear function that models the number of books left after w weeks would be
b = 1850 - 120w
