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DENIUS [597]
3 years ago
5

I’m very smart. My hair is dark. I love to eat honey, insects, and bark. What am I?

Biology
2 answers:
VMariaS [17]3 years ago
5 0
The answer is honey bee
taurus [48]3 years ago
4 0

Answer:

<em>honey bee</em>

Hope this helps!

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Do lysosomes contain chromosomes ?
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No. Instead they contain enzymes.

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Which of the following statements concerning eukaryotic cells are true? Check all that apply.
Free_Kalibri [48]

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They are typically larger than prokaryotic cells

The DNA of a eukaryotic cell is contained in the cell nucleus.

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3 years ago
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In the Cori cycle, when glucose is degraded by glycolysis to lactate in muscle, the lactate is excreted into the blood and retur
Flauer [41]

Answer:

The correct answer is A. The statement is true.

Explanation:

Muscle obtains ATP from glycolysis. When exercise conditions are anaerobic, glucose is degraded to lactate. Lactate is exported into the circulation and is taken up by the liver. The liver synthesizes glucose again from lactate via the gluconeogenic pathway. These two metabolic pathways that allow the coupling of the function of two tissues is what is known as the Cori cycle. The energy cost is 4 P bonds / each glucose that travels both glycolytic-gluconeogenic pathways.

6 0
3 years ago
In watermelons, bitter fruit (B) is dominant over sweet fruit (b), and yellow spots (S) are dominant over no spots (s). The gene
NikAS [45]

Answer:

A) 9:3:3:1

B) All bitter fruit, yellow spotted offsprings

C) Phenotypes are bitter yellow spotted (4), bitter no spot (4), sweet yellow spot (4), and sweet no spot (4). 1:1:1:1

Explanation:

This is a typical dihybrid cross involving two genes, one coding for fruit taste and the other for spot color. The allele for bitter taste (B) and yellow spot (S) is dominant over the allele for sweet taste (b) and no spot (s) respectively.

Hence, a heterozygous F1 resulting from a cross between an homozygous dominant (bitter fruit, yellow spot) and homozygous recessive (sweet fruit, no spot) will have a BbSs genotype. The heterozygous F1 offsprings are self-crossed and produce gametes BS, Bs, bS, bs. (See punnet square). The F2 offsprings will have the following phenotypes: Bitter fruit, yellow spot (9)

Bitter fruit, no spot (3)

Sweet fruit, yellow spot (3)

Sweet fruit, no spot (1)

Back cross between a F1 offspring (BbSs) and homozygous dominant parent (BBSS) will produce all bitter fruit, yellow spot offsprings (see attached image). BBSS (4), BBSs (4), BbSS (4), and BbSs (4) are the offsprings' genotypes.

For the back cross between a F1 offspring (BbSs) and a homozygous recessive (bbss) parent, the Phenotypes with their proportions are as follows:

Bitter fruit, yellow spot (BbSs, 4)

Bitter fruit, no spot (Bbss, 4)

Sweet fruit, yellow spot (bbSs, 4)

Sweet fruit, no spot (bbss, 4).

4 0
3 years ago
Warmer ocean surface water would most likely be found near ___.
KiRa [710]

The warm ocean water is usually found near the top surface of the ocean. The sun makes the surface of the ocean warm and thus heat up its water. This heat is later mixed by the winds and sea waves from top to beneath the ocean surface. The temperature of the surface is usually warmer than the water at depths as it does not receive sun light. The average ocean temperature at the surface is 17 degree Celsius while at greater depth the temperature falls down to 0 to (-3) degree Celsius


8 0
3 years ago
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