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2 years ago

Help pleaseeeeeeeeeeee

Mathematics

2 answers:

slega [8]2 years ago

8 0

Answer:

C. 72

Step-by-step explanation:

your are given the adjacent length of 2.4 cm and the hypotenuse of 7.8cm

so we know cos = adjacent/ hypotenuse

so to find the angle of cos you use the inverse of cos^-1(2.4/7.8)

after typing into calculator you should get about 72

Triss [41]2 years ago

6 0

Answer:

Step-by-step explanation:

cos(0)= Adjacent/Hypotenuse

cos(0)= n/p

cos(0)=2.4/7.8

cos(0)=4/13

(0)=cos‐¹(4/13)

(0)=72.07978686

(0)=72°

angle (0)= 72°

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Http://prntscr.com/lkz30r What is the value of x? 28 20 36 17

ivolga24 [154]

This is a question that can be solved with Pythagorean Theorem since it is a right triangle. The longest side, 29, is the hypotenuse and the sides 21 and x are the legs. So, the Pythagorean Theorem states,

$c^{2}= a^{2}+ b^{2}$

Where,

c is the Hypotenuse, a and b are the legs. Putting the respective values gives us,

$(29)^{2}= (21)^{2} +x^{2} \\841=441+x^{2} \\400=x^{2} \\20=x$

So, 20 is the side length of x.

ANSWER: 20

5 0

3 years ago

Read 2 more answers

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

Springer was a political candidate running for Congress. He was operating on a tight budget and instructed his campaign staff no

tatuchka [14]

Answer

In the event that a purchase was made for a campaign without it being managed by the staff in charge of this management, with a proposal not to pay because the person who bought it was not this staff but the candidate, the selling company, Dubychek , is in everything correct when alleging the payment, the candidate knew of the situation and it is known that the representative, goes in the name of this candidate.

6 0

3 years ago

Pls help im not smart enough ;-;

evablogger [386]

PART1:

First Combination:
Pizza ($7) + Chicken Strips ($6) + Biscuits ($3) + Grapes ($4) = $20

Second Combination:
Dog Food ($13) + Bread ($3) + Crackers ($2) + Broccoli ($2) = $20

Third Combination:
Shampoo ($4) + Tissues ($3) + Pizza ($7) + Eggs ($3) + Biscuits ($3) = $20

PART 2:

First Combination:
$7.20 + $5.70 + $2.90 + $3.70 = $19.60
No, I wouldn’t have gone over the limit

Second Combination:
$13.40 + $3.50 + $2.00 + $1.90 = $20.80
Yes, I would have gone over the limit

Third Combination:
$3.50 + $2.60 + $7.20 + $2.50 + $2.90 = $18.70
No, I wouldn’t have gone over the limit

Hope this helps!!

7 0

3 years ago

Jane and 3 friends decided to split the cost of a pizza evenly. The total cost was $25.48. How much does each friend have to pay

erma4kov [3.2K]

Answer:

$6.37

Step-by-step explanation:

Jane and 3 friends = Jane + another 3 people

= 4 people in total

Total Cost of pizza = $25.48

If 4 people split $25.48 evenly,

Amount each friend has to pay = Total Cost of pizza/Total number of people

= $25.48/4

= $6.37 per friend

Each friend has to pay $6.37 each if $25.48 is splitted evenly amongst them

6 0

3 years ago