Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)
Answer:
The proportion of exam scores that are lower than Irina's score is 0.9938
Step-by-step explanation:
<u>Data</u>
- standard deviation (sd): 6 points
- value of interest (x): 95 points
z-score is computed as follows:
z = (x - mean)/sd
z = (95 - 80)/6 = 2.5
We want to find:
P(z < 2.5)
From the table attached:
P(z < 2.5) = 0.9938
We are looking to figure out the size of m<CAB
Since line AB is parallel to the line CD, m<CAB corresponds to m<ECD which means the size of the angles equals
m<ECD can be found by using the fact that angles in a triangle add up to 180°,
hence, 180°-58°-43°=79°
The size of m<CAB is 79°
The diagonals of a kite meet at a right angle.
3/2/3 - 1/1/4
= 3/8/12 - 1/3/12
= 2/5/12
i am a mathematics teacher. if anything to ask please pm me