If the length is 2ft longer than it’s width
Let’s assume width as X and so the length will be X+2
Perimeter=40ft
Putting the values into a equation, we get,
X+2+X=40
=2X+2=40
=2X=38
=X=19
Therefore
Length =X+2=19+2
=21ft
Width=X=19ft
Area of rectangle =lxb
= 21x19
3992ft
HOPE IT WAS HELPFUL :)
Answer:-4y^3-12y^2-7x
Step-by-step explanation:if you collect the liked terms it will add up to get that
Answer:
Explanation:
We can factor the numerator and denominator as;
(
x
−
2
)
(
x
−
1
)
2
x
(
x
−
1
)
We can now cancel common term in the numerator and denominator:
(
x
−
2
)
(
x
−
1
)
2
x
(
x
−
1
)
⇒
x
−
2
2
x
However, we cannot divide by
0
so we must exclude:
2
x
=
0
⇒
x
=
0
and
x
−
1
=
0
⇒
x
1
x
2
−
3
x
+
2
2
x
2
−
2
x
=
x
−
2
2
x
Where:
x
≠
0
and
x
≠
1
Or
x
2
−
3
x
+
2
2
x
2
−
2
x
=
x
2
x
−
2
2
x
=
1
2
−
1
x
Where:
x
≠
0
and
x
≠
1
Step-by-step explanation:
