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kifflom [539]
3 years ago
8

The angles in a triangle are such that one angle is 120 degrees more than the smallest angle, while the third angle is 3 times a

s large as the smallest angle. Find the measures of all three angles.
Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer:

a = 132; b = 12; c = 36

Step-by-step explanation:

a = b + 120

b = b

c = 3b

a + b + c = 180

(substitute these into the above equation)

b + 120   + b    + 3b  = 180

5b + 120 = 180

       -120    -120

5b = 60

/5     /5

b = 12

(substitute b back into the first equations)

a = (12) + 120 = 132

b = (12)

c = 3(12) = 36

(check: 132 + 12 + 36 = 180)

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Answer:

a:d=7:9

Step-by-step explanation:

We have a system with 3 equation:

\frac{a}{b}=\frac{2}{3}\\\frac{b}{c}=\frac{4}{3}\\\frac{c}{d}=\frac{7}{8}

If we multiply all of these equations, then we have:

\frac{a}{b}*\frac{b}{c}*\frac{c}{d}=\frac{2}{3}*\frac{4}{3}*\frac{7}{8}\\\frac{a*b*c}{b*c*d}=\frac{2*4*7}{3*3*8}\\\frac{a}{d}=\frac{56}{72}

If we simplify this fraction dividing by 9, then:

\frac{a}{d}=\frac{56:9}{72:9}=\frac{7}{9}

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3 years ago
Is there any destiny 2 fans here. here's my question<br> 85×35×999×63=
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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2
Mekhanik [1.2K]

Answer:

x=1

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Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either   \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t  = e^−2(0)  = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt}  = -2te^{-2t}  = -2(0)e^{-2(0)}  = 0

The vector equation of the tangent line is

(1, 0, 1) +s(0,1,0)= (1, s, 1)

The parametric equations are:

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Which of the following is equivalent to f(x)?
Fynjy0 [20]

Answer:

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Step-by-step explanation:

<u>Given function:</u>

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<u>Equivalent expression is:</u>

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Correct choice is D

6 0
3 years ago
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