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Stella [2.4K]
3 years ago
7

(X^3)^3 = x^n Solve for n

Mathematics
1 answer:
Blababa [14]3 years ago
3 0
Solve for n :
N=9
...........
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2 log x + log 11<br> WILL MARK BRAINLIEST
tester [92]

Answer:

log(11 {x}^{2} )

Step-by-step explanation:

2logx + log11 \\  \\  = log {x}^{2}  + log11 \\  \\  = log( {x}^{2}  \times 11) \\  \\  = log(11 {x}^{2} )

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PLEASE CAN SOMEONE ANSWER THIS <br><br> y=8.2x+459=
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If 50% of a number is 18 what is 75% of the number
den301095 [7]

Answer:

A) 50% of 36 is 18

B) 75% of 36 is 27

Step-by-step explanation:

6 0
3 years ago
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The difference of two perfect cubes is 386. If the cube root of the smaller of the two numbers is 7, then the cube root of the l
choli [55]

Answer:

9

Step-by-step explanation:

Let the two perfect cubes be x and y where x > y.

According to the given conditions:

{x}^{3}  -  {y}^{3}  = 386...(1) \\ y = 7...(2) \\ plug \: y = 7 \: in \: equation \: (1) \\  {x}^{3}  -  {7}^{3}  = 386 \\ {x}^{3}  -  343 = 386 \\ {x}^{3}     = 343  +  386 \\ {x}^{3}     = 343  +  386 \\ {x}^{3}   = 729 \\ x =  \sqrt[3]{729}  \\ x = 9

Thus the cube root of the larger number is 9.

8 0
3 years ago
Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)
Lisa [10]

Answer:

f(x) = 4x^2 - 3x + 6

Step-by-step explanation:

Quadratic function is given as f(x) = ax^2 + bx + c

Let's find a, b and c:

Substituting (0, 6):

6 = a(0)^2 + b(0) + c

6 = 0 + 0 + c

c = 6

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

f(x) = ax^2 + bx + c

16 = a(2)^2 + b(2) + 6

16 = 4a + 2b + 6

16 - 6 = 4a + 2b + 6 - 6

10 = 4a + 2b

10 = 2(2a + b)

\frac{10}{2} = \frac{2(2a + b)}{2}

5 = 2a + b

2a + b = 5 => (Equation 1)

Substituting (3, 33), and c = 6

f(x) = ax^2 + bx + x

33 = a(3)^2 + b(3) + 6

33 = 9a + 3b + 6

33 - 6 = 9a + 3b + 6 - 6

27 = 9a + 3b

27 = 3(3a + b)

\frac{27}{3} = \frac{3(3a + b)}{3}

9 = 3a + b

3a + b = 9 => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

3a + b = 9

2a + b = 5

a = 4

Replace a with 4 in equation 2.

2a + b = 5

2(4) + b = 5

8 + b = 5

8 + b - 8 = 5 - 8

b = -3

The quadratic function that represents the given 3 points would be as follows:

f(x) = ax^2 + bx + c

f(x) = (4)x^2 + (-3)x + 6

f(x) = 4x^2 - 3x + 6

6 0
3 years ago
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