The 94 ft. by 50 ft dimensions of the court obtained from a similar question posted online, gives;
a. The ordered pair representing the location of the player in the bottom right corner is (47, -25)
b. The distance traveled by the ball obtained using Pythagorean theorem, is approximately 53.2 feet.
<h3>How can Pythagorean theorem be used to find the distance the ball travels?</h3>
The possible dimensions of a rectangular court obtained from a similar question posted online are;
Length of the basketball court = 94ft.
Width of the basketball court = 50 ft.
From the question, we have;
Location of the court center = The origin of a coordinate plane
a. The ordered pair that represent the location of a player in the bottom right corner is found as follows;
Let (x, y) represent the coordinates of the bottom right corner of the court, we have;
Horizontal distance from the center of the court (the origin) to the right boundary of the court, <em>x </em>= (94 ft.)/2 = 47 ft.
Vertical distance from the center to bottom of the court, <em>y </em>= (50 ft.)/2 = 25 ft.
Following the convention of points to the right and above the origin being positive, while points below the origin are negative, we have;
The ordered pair (the coordinates of the player) that represents the location of the player in the bottom right corner is therefore;
b. The distance, <em>d</em>, that the ball travels is given by Pythagorean theorem as follows;
d = √((47 - 0)² + ((-25) - 0)²) = √(2834) ≈ 53.2
- The ball travels approximately 53.2 feet.
Learn more about Pythagorean theorem here:
brainly.com/question/21332040
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