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2 years ago

Factor the quadratic expression x2-19x+88 (x+)(x+) ^ Where the answer would go

Mathematics

1 answer:

ipn [44]2 years ago

7 0

Answer:

(x+8)(x+11)

Step-by-step explanation:

When you factor a quadratic by the form:

$x^{2} + bx + c$

you are looking for two numbers, 'q' and 'r', which ADD to 'b' and MULTIPLY to 'c'.

In this case, some example numbers that multiply to 88 are:

±1, ±2, ±4, ±8, ±11, ±44, ±88.

Since they must add to 19, then you can figure out through some trial and error that the numbers are 8 and 11.

8*11 = 88

8+11 = 19

So, the answer is (x+8)(x+11)

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Answer:

The remainder is 1

Step-by-step explanation:

Given the Fibonacci sequence

F_1 = F_2 = 1, and

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We want to find the remainder when F_(1999) is divided by 5.

Let us write the first 20 numbers of the sequence in (mod 5). They are

F_1 = 1,

F_2 = 1,

F_3 = 2,

F_4 = 3,

F_5 = 5 = 0 (mod 5),

F_6 = 3,

F_7 = 3,

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F_(17) = 2

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Now, 1999 = 19(mod 20)

The 19th number in the sequence is 1.

So, the remainder is 1.

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3 years ago

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Answer:

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3 years ago

Factor the quadratic expression x2-19x+88 (x+__)(x+__) ^ Where the answer would go​

Factor the quadratic expression x2-19x+88 (x+)(x+) ^ Where the answer would go