It's always easier to understand a concept by looking at specific examples with pictures, so I suggest looking at the dilation examples below first...before you try to internalize the steps listed below and that explain the general formula for dilating a point with coordinates of (2,4) by a scale factor of <span><span>12</span><span>12</span></span>.
<span><span>1) multiply both coordinates by scale factor<span>(<span><span>2⋅<span>12</span>,4⋅<span>12</span></span><span>2⋅<span>12</span>,4⋅<span>12</span></span></span>)</span></span><span>2)
2. Simplify(1,2)</span><span>3)
3. Graph(if required)<span> </span></span></span>
Answer:
14 18/25 is the answer
Step-by-step explanation:
23/5 x 16/5
23x16
5x5
368/25=14 18/25
The second leftover expression is not o(a+b). It is 6(a + b). I have attached the correct question to depict that.
Answer:
The equivalent expressions are;
8a + 2 and 6a + 6b
Step-by-step explanation:
The two leftover expressions are given as;
2(4x + 1) and 6(a + b)
In algebra, equivalent expressions are simply those expressions which when simplified, give the same resulting expression as the initial one.
Thus simply means expanding or collecting like times to make it clearer.
Now, in our question, like terms have already been collected. This means that to find an equivalent expression, we will just expand the bracket.
Thus;
2(4x + 1) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
8x + 2
Similarly,
6(a + b) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
6a + 6b
Thus;
The equivalent expressions are;
8a + 2 and 6a + 6b
The answer should be C but I’m not for sure ask your teacher sorry!!
Answer:
The length of the rectangular field is 12 ft and the width is 5 ft.
Step-by-step explanation:
The area of a rectangle is:
![\text{Area} = \text{length}\times \text{width}](https://tex.z-dn.net/?f=%5Ctext%7BArea%7D%20%3D%20%5Ctext%7Blength%7D%5Ctimes%20%5Ctext%7Bwidth%7D)
The area of a rectangular field is, <em>A</em> = 60 ft.
The length of the field is:
l = w + 7
Compute the width of the field as follows:
![\text{Area} = \text{length}\times \text{width}](https://tex.z-dn.net/?f=%5Ctext%7BArea%7D%20%3D%20%5Ctext%7Blength%7D%5Ctimes%20%5Ctext%7Bwidth%7D)
![60=(w+7)\times w\\\\60=w^{2}+7w\\\\w^{2}+7w-60=0\\](https://tex.z-dn.net/?f=60%3D%28w%2B7%29%5Ctimes%20w%5C%5C%5C%5C60%3Dw%5E%7B2%7D%2B7w%5C%5C%5C%5Cw%5E%7B2%7D%2B7w-60%3D0%5C%5C)
Factorize the last equation by splitting the middle term as follows:
![w^{2}+7w-60=0\\w^{2}+12w-5w-60=0\\w(w+12)-5(w+12)=0\\(w-5)(w+12)=0](https://tex.z-dn.net/?f=w%5E%7B2%7D%2B7w-60%3D0%5C%5Cw%5E%7B2%7D%2B12w-5w-60%3D0%5C%5Cw%28w%2B12%29-5%28w%2B12%29%3D0%5C%5C%28w-5%29%28w%2B12%29%3D0)
Now, since the width of rectangular field cannot be negative, the width is 5 ft.
Compute the length as follows:
l = w + 7
= 5 + 7
= 12
The length of the rectangular field is 12 ft.