Answer:
Step-by-step explanation:
<u><em>Part B:</em></u>
The center of the circumscribed circle around a triangle is equidistant from vertices of that triangle. To find the circumcenter need to draw at least two perpendicular bisectors to the sides of the given triangle. Point of intersect of them is center of the circumscribed circle.
<u><em>Part C:</em></u>
Coordinates of the midpoint of line BC ( y = - 1 ) are
( 
, 
) = <em>( - 2 , - 1 )</em> and the equation of the line ⊥ to BC is <em>x = - 2</em>
Because BC is ║ to x-axis and m∠A is 90° , the center of the circle is midpoint of BC and r = 
= 4
9514 1404 393
Answer:
A) 5x+12 = -12x-12
D) 5x+12 = -5x-12
Step-by-step explanation:
If you subtract the right side expression from both sides, you will get an equation with something equal to zero. If the 'something' has a variable in it, there is exactly one solution.
A: (5x+12) -(-12x-12) = 17x+24 = 0 . . . one solution
B: (5x+12) -(5x-5) = 17 = 0 . . . . no solutions
C: (5x+12)-(5x+12) = 0 = 0 . . . . infinite solutions
D: (5x+12) -(-5x-12) = 10x +24 = 0 . . . one solution
Answer:
14a^2
Step-by-step explanation:
3a^2+4a^2+7a^2
Combine like terms
Factor out a^2
a^2(3+4+7)
a^2(14)
14a^2
The factors of 117 are: 1, 3, 9, 13, 39, and 117
The factors of 99 are: 1, 3, 9, 11, 33, and 99
The factors of 126 are: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126
The greatest common factors of 117, 99, and 126 are: 1, 3, and 9. And according to your answer choices your answer is C. 9
<span>C(15,9) * (1/2)^9 * (1/2)^6 = 5005/32768 = .153 approx</span>
