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kolbaska11 [484]
3 years ago
5

Please help me with this!!!!

Mathematics
2 answers:
Crazy boy [7]3 years ago
5 0

Answer:

The answer is C

Step-by-step explanation:

VMariaS [17]3 years ago
4 0

Answer:

<em> </em><em>c</em><em> </em><em>is</em><em> </em><em>correct</em><em> </em>

<em>hope</em><em> </em><em>it</em><em> </em><em>helped</em>

You might be interested in
( 7x + 1/2) + ( 7x - 7 and 1/2) Simplify
pishuonlain [190]

Answer:

The answer will be 7(2x - 1)

Step-by-step explanation:

1) Convert 7 and 1/2 to improper fraction. Use this rule: a b/c = ac + b/c

7x +  \frac{1}{2}  + 7x -  \frac{7 \times 2 + 1}{2}

2) Simplify 7 × 2 to 14 .

7x +  \frac{1}{2}  + 7x  -  \frac{14 + 1}{2}

3) Simplify 14 + 1 to 15.

7x +  \frac{1}{2}  + 7x -  \frac{15}{2}

4) Collect like terms.

(7x + 7x) + ( \frac{1}{2}  -  \frac{15}{2} )

5) simplify.

14x - 7

6) Factor out the common term 7.

7(2x - 1)

Therefor, the answer is 7( 2x - 1 ).

7 0
3 years ago
PLZ SOLVE ASAP Solve for f. -11f=7(1-2f)+5
viktelen [127]

Answer:

f = 4

Step-by-step explanation:

Step 1: Distribute

-11f = 7 - 14f + 5

Step 2: Combine like terms

-11f = 12 - 14f

Step 3: Add 14f to both sides

3f = 12

Step 4: Divide both sides by 3

f = 4

4 0
4 years ago
Read 2 more answers
do you think that a negative sign affects whether or not a number is rational number? Use -8/5 an example.
lina2011 [118]

-8/5 is a rational number because in order to be a rational number it must be able to be written as a fraction. -8/5 is a fraction; therefore, the negative does not affect it.

5 0
4 years ago
The function f has first derivative given by f'(x)=(x)^1/2/1+x+x^3. What is the x-coordinate of the inflection point of the grap
Anestetic [448]
Inflection at f'(x) = 0 
<span>
x^1/2 / (1 + x + x^3) = 0 </span>

<span>The x coordinate is x = 0 </span>
<span>
or "C" from your choices there. </span>

<span>The simplest way is to notice that this happens when x = 0. The reason is you got: </span>
<span>
x^1/2 / (some expression) </span>
<span>
at x = 0 the numerator is 0 so unless the denominator is also 0 the result is 0. </span>
<span>
The denominator for x = 0 is 1 so you get </span>
<span>
0/1 = 0.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
4 0
3 years ago
PLEASE HELPP also sorry the photo is sideways
dybincka [34]
<h2>a) Select all that apply</h2>

\overline{LL'}, \ \overline{MM'} \ and \ \overline{NN'}<em> are each perpendicular to the line of reflection</em>

<em></em>

This option is the only one that is correct. The line of reflection is  y=-1. When we talk about reflection, we are talking about reflecting across a line, or axis. Reflecting a shape means looking at the mirror image on the other side of the axis. So in this case, this mirror is the line of reflection.  As you can see, these three segments \overline{LL'}, \ \overline{MM'} \ and \ \overline{NN'}<em> </em>form a right angle at the point each segment intersects the line y=-1.

<h2>b) Find each length</h2>

Since the line y=-1 is an axis that allows to get a mirror image, therefore it is true that:

\overline{LS}=\overline{L'S} \\ \\ \overline{MT}=\overline{M'T} \\ \\ \overline{NU}=\overline{N'U}

To find those values \overline{LS}, count the number of units you get from the point S to L, which is 3 units. Do the same to find \overline{MT} but from the point T to M, which is 6 units and finally, for \overline{NU} but from the point U to N, which is 4 units. Therefore:

\overline{LS}=\overline{L'S}=3 \ units \\ \\ \overline{MT}=\overline{M'T}=6 \ units \\ \\ \overline{NU}=\overline{N'U}=4 \ units

<h2>c) Correct Statement</h2>

<em>The line of reflection is the perpendicular bisector of each segment joining a point and its image. </em>

<em />

A bisector is the line dividing something into two equal parts. In this case, the line of reflection divides each segment into two equal parts and is perpendicular because this line form a right angle with each segment. As we demonstrated in a) each segment is perpendicular to the line of reflection, so the first statement is false. On the other hand, each side of the original triangle is not perpendicular to its image and this is obvious when taking a look at the figure. Finally, as we said the line of reflection is perpendicular to each of the mentioned segments, so they can't be parallel as established in the last statement.

5 0
3 years ago
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