What method of factoring should first be used? 49v^4-u^8

Mathematics

1 answer:

Vinvika [58]2 years ago

6 0

Answer:

Difference of perfect square

Step-by-step explanation:

→ Greatest common factor is wrong because there is only one integer

→ Trinomial factoring is wrong because if the brackets were split into 3, there would be more than 2 variables

→ Does not factor is wrong because it does factor

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One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

Suppose that 13 inches of wire costs 78 cents. At the same rate, how much (in cents) will 37 inches of wire cost?

Neko [114]

78/13 = 6 cents per inch
37 * 6 = 222

5 0

3 years ago

Read 2 more answers

Factor -12n-24 Pleasee helppp

Novosadov [1.4K]

-12 n - 24 = -12 (n+2)

-12 (n+2) is the answer

7 0