Here
we can see that the problem gives us the length of a sandwich of x =
1.2. The problem also asks us for the expression that better
represents the approximate length of the crust given among the
options above. Here we simply have to substitute x to each of the
choices.
The
answer is B) x = 8x² + 34; 45.52 centemiters
I
hope it helps, Regards.
Answer:
Ty, you too!
Step-by-step explanation:
Hope you have a good day.
Actually Welcome to the Concept of the Surface Areas and Volumes.
Since, Volume of cone = 1/3 π r^2 h,
here, r = 10 Inches and h= 12 inches, also π =3.14
so, VOC = 1/3 π (10)^2 × (20)
VOC = 1/3(3.14)(100)(20)= 2093.33 inch^3
=> so the volume of the cone is 2093.33 cubic inches.
Answer:
See below
Step-by-step explanation:
Part A
<em><u>Formula</u></em>
M = 2/3 * log(E/Eo)
<em><u>Givens</u></em>
M = ??
E = 2 * 10^15 joules
Eo = 10^4.4
<em><u>Solution</u></em>
M = (2/3) * log(2 * 10^15 / 10^4.4)
M = (2/3 ) log (7.96 * 10 ^ 11)
M = (2/3) * 11.901
M = 7.934
Part B
What the question is saying is that E/Eo = 10000
You don't have to figure out exact values.
M = 2/3 * log(10000)
M = 2/3 * 4
M = 8/3 or 2 2/3 or 2.66667
If you have choices, please list them.
Divide 252 by 21.
21 times 12 = 252
12 is 9 units shorter than 21.
so the answer is 12 inches by 21 inches
you work backwards from the area
area = width times length
a = wl
we know w is 9 units shorter than the length
so now we have the equation 252=(l-9) times l
plug in 21 for l and then solve there is your answer.
