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3 years ago

HELP ASAP TYSM TYSM What is the surface area of the square pyramid? I put a picture! ⬇️

Mathematics

1 answer:

levacccp [35]3 years ago

3 0

Answer:

the surface area is 133cm.

7 x 7 is 49

7 x 6 is 42.

42 divided by 2 is 21.

21 x 4 is 84

So 84 + 49 is 133.

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Convert 30 feet per second into yards per minute

olga55 [171]

Answer:

30 feet converted into yards per minute would come out to 600 yards per minute

Step-by-step explanation:

multiply speed value by 20

30x20=600

Hope this helped :)

6 0

3 years ago

Read 2 more answers

What is the reciprocal of 5/8

V125BC [204]

The reciprocal of 5/8 is 8/5 all you have to do is flip it.
so if you are looking for the reciprocal to 2, then it is 1/2 because of the fraction properties

7 0

3 years ago

Please help me write quadratic equation given the roots and the leading coefficient

Pie

Answer:

Example Question: f(x) = 2x^2 + 2x - 1

If the leading coefficient is positive, the graph will be opening up (U) if the leading coefficient is negative, the graph will be opening down (n)

Roots are the x-intercepts that help find the axis of symmetry (add the two roots together and divide the result by 2 to get the axis of symmetry)

To find the vertex, simply imput the axis of symmetry into the given equation.

And that’s about it.

Step-by-step explanation:

I don’t know what you’re asking for??

5 0

2 years ago

Carlos and Maria drove a total of 228 miles in 4.6 hours. Carlos drove the first part of the trip and averaged

aleksklad [387]

Answer:

around 228

Step-by-step explanation:

8 0

3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago