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dalvyx [7]
3 years ago
7

Identify a pattern in the given list of numbers. Then use this pattern to find the next number.​ (More than one pattern might​ e

xist, so it is possible that there is more than one correct​ answer.)
​27,-9 ​,3 ​,-1 ​,___
Mathematics
2 answers:
horrorfan [7]3 years ago
5 0
Answer:
Divide by - 3
Step-by-step explanation:

The given list of numbers isn’t provided but the pattern will be divided by - 3
Artist 52 [7]3 years ago
3 0
It’s being divided by -3, so that means the next number is 1/3, or one third
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7

Step-by-step explanation:

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What are the prime factors of 4,725
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Solve the equation by the Quadratic Formula. x^2+3=9x
Nadya [2.5K]

Answer:

Step-by-step explanation:

Rearrange the given x^2+3=9x in standard quadratic form:

1x^2 - 9x +3 = 0

Then the three coefficients are a = 1, b = -9 and c = 3.

The discriminant is √(b^2 - 4ac), or √(81 - [1][3]), or √78.

                                        ± √78

Thus, the roots are x = ----------------

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3 years ago
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The length of the rectangle is x cm. The length of a diagonal of the rectangle is 8 crn. The perimeter of the rectangle is 20 cm
klemol [59]

Answer:

x^2-10x+18=0

<em>a</em> = -10 and <em>b</em> = 18.

Step-by-step explanation:

Let <em>w</em> represent the width of the rectangle.

We are given that the perimeter of the rectangle is 20 cm, this means that:

20=2(x + w)

Let's put <em>w</em> in terms of <em>x</em>. Divide both sides by two:

10=x+w

And solve for <em>w:</em>

<em />w=10-x<em />

So, the rectangle measures <em>x</em> by (10 -<em> x</em>) cm.

<em />

According to the Pythagorean Theorem:

a^2+b^2=c^2

<em>a</em> and <em>b</em> are the legs and <em>c</em> is the hypotenuse.

Substitute <em>x</em> for <em>a, w</em> for <em>b</em>, and 8 for <em>c:</em>

<em />x^2+w^2=8^2<em />

Simplify and substitute:

x^2+(10-x)^2=64

Square:

x^2+(100-20x+x^2)=64

Isolate the equation. So:

2x^2-20x+36=0

Since the leading coefficient is one, divide both sides by two:

x^2-10x+18=0

Therefore, <em>a</em> = -10 and <em>b</em> = 18.

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