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Julli [10]
3 years ago
5

exFormula1" title="\frac{t}{3\\} + \frac{1}{6} = \frac{1}{2}" alt="\frac{t}{3\\} + \frac{1}{6} = \frac{1}{2}" align="absmiddle" class="latex-formula"> ( show step by step)
Mathematics
2 answers:
I am Lyosha [343]3 years ago
7 0

t/3 + 1/6 = 1/2

Multiply both sides of the equation by six
2t+1=3

Move constant to the right-hand side and change its sign
2t=3-1

Subtract the numbers
2t=2

Divide both sides of the equation by 2
t=1

Solution:
t=1
mart [117]3 years ago
4 0

Answer:

Step-by-step explanation:

Sorry Difficult

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One focus of a hyperbola is located at (−6, 2). One vertex of the hyperbola is located at (−4, 2). The center is (−1, 2).
Valentin [98]

Answer:

(x+1)^2/9 - (y-2)^2/16 = 1

Step-by-step explanation:

As the center and the vertex of the hyperbola forms a horizontal segment (they have the same y value), we can use the hyperbola equation with horizontal axis:

(x-h)^2/a^2 - (y-k)^2/b^2 = 1

For this equation, the center of the hyperbola is (h,k), the vertix is (h±a, k) and the focus is (h±c, k), where c^2 = a^2 + b^2

So if the center is (-1,2), we have h = -1 and k = 2

If the vertex is (-4,2), we have that h-a = -4, so a = 3

If the focus is (-6,2), we have that h-c = -6, so c = 5

Now, finding b, we have:

5^2 = 3^2 + b^2

b = 4

So our equation is:

(x+1)^2/9 - (y-2)^2/16 = 1

8 0
4 years ago
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Pls help asap!!!
Westkost [7]

Answer:

Step-by-step explanation:

Let x be the random variable. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,

z = (x - µ)/σ

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µ = population mean

σ = standard deviation

From the information given,

µ = 474

σ = 32

x = 514

The probability of being below 514 is expressed as P(x < 514)

For x = 514,

z = (514 - 474)/32 = 1.25

Looking at the normal distribution table, the probability value corresponding to area below the z score is 0.89

Therefore,

P(x < 514) = 0.89

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Answer:

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