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Alisiya [41]
3 years ago
10

Simplify 14 to the 15th power over 14 to the 5th power.

Mathematics
1 answer:
cluponka [151]3 years ago
6 0

14^15/14^5=14^(15-5)=14^10

Hope this kinda helps !!
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140÷(x+9)+(x+4)² when x =1 show work​
Dmitrij [34]

Answer:

39

Step-by-step explanation:

If x=1, then it's equal to 140/(1+9, or 10)+(1+4, or 5)^2, and that is equal to 140/10+5^2, or 140/10+25, and 140/10=14, and 14+25=39

brainliest pls

4 0
2 years ago
Can somebody explain to me how to do this
11111nata11111 [884]

Answer:below hopes it helps the link should help aswell

Step-by-step explanation:

https://mathsolver.microsoft.com/en/solve-problem/%60frac%7B%2010%20%7B%20q%20%20%7D%5E%7B%205%20%20%7D%20%20%20%7B%20w%20%20%7D%5E%7B%207%20%20%7D%20%20%20%20%7D%7B%202%20%7B%20w%20%20%7D%5E%7B%203%20%20%7D%20%20%20%20%7D%20%20%20%60frac%7B%204%20%7B%20%60left(%20%7B%20q%20%20%7D%5E%7B%206%20%20%7D%20%20%20%60right)%20%7D%5E%7B%202%20%20%7D%20%20%20%20%7D%7B%20%20%7B%20w%20%20%7D%5E%7B%20-5%20%20%7D%20%20%20%20%7D

3 0
3 years ago
Three stamps can be attached to each other in various ways.how many ways might three stamps be attached?
ivanzaharov [21]
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula. 
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C. 
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space. 
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.


8 0
3 years ago
-5+7=7+-5 is this number sentence true or false
vovikov84 [41]

Answer: True

Step-by-step explanation:

We can simplify each of the expressions on either side to see if they are equal.

Left side: -5+7=7-5= 2

Right side: 7+-5=7-5= 2

Yes, they are equal.

7 0
1 year ago
Read 2 more answers
A line with a slope of 3 passes through the point (2, 5). Write an equation for this line in point-slope form.
Phantasy [73]

Answer:

slope = 3

point (2, 5)

b = y - m*x

b = 5 -3*2

b = -1

Then we enter the slope and the value of b into this equation:

y = mx + b

y = 3x -1

Source: https://www.1728.org/distance.htm

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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