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Step2247 [10]
3 years ago
11

Christopher is analyzing a circle, y^2 + x^2 = 121, and a linear function g(x). Will they intersect?

Mathematics
1 answer:
Sav [38]3 years ago
7 0
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12   (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case, 
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.

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\large{m =  \frac{10 - ( - 8)}{2 - 10} } \\  \large{m =  \frac{10 + 8}{ - 8} } \\  \large{ m =  \frac{18} { - 8} \longrightarrow  \frac{9}{ - 4} } \\  \large \boxed{m =  -  \frac{9}{4} }

Answer

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6 0
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Read 2 more answers
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Step-by-step explanation:

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