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geniusboy [140]
3 years ago
10

HURRY!! If the pattern in the table is extended to represent more equivalent ratios for 2:6, which pair of numbers would be in t

he columns? A multiplication table. In the column labeled 2, the numbers 2, 4, 6, 8, 10, 12, 14, 16, and 18 are highlighted. In the column labeled 6, the numbers 6, 12, 18, 24, 30, 36, 42, 48, and 54 are highlighted. 20 would be in the column for 2, and 60 would be in the column for 6. 20 would be in the column for 2, and 60 would be in the column for 6. 20 would be in the column for 6, and 60 would be in the column for 2. 20 would be in the column for 6, and 60 would be in the column for 2. 20 would be in the column for 2, and 56 would be in the column for 6. 20 would be in the column for 2, and 56 would be in the column for 6. 20 would be in the column for 6, and 56 would be in the column for 2.
Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

Answer:

The answer is A

Step-by-step explanation:

got it right on edge2021

please mark me as a brainlist please

vlada-n [284]3 years ago
4 0

Answer:

B

Step-by-step explanation:

That's even, Steven.

That's odd, Mr. Todd.

<h2><u><em>Please mark as Brainliest!!!</em></u></h2>
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15 - 12 indicated operation
Rashid [163]

Answer: 3

Step-by-step explanation:

12+3 =15

6 0
3 years ago
There are 4 blue boxes and 2 white boxes in a bag. What is the probability of picking 1 blue box followed by another white box?
ira [324]
2/5 chance that you would pick out a white box
3 0
3 years ago
Which expression is equivalent to 2(x^2-1) + 3x(x-4) (please show work)
Tema [17]

Answer:

5x^2-12x-2

Step-by-step explanation:

Use distributive property, then add like terms. See file below for steps.

4 0
3 years ago
Determine whether the two figures are similar. If so, give the similarity ratio of the smaller figure to the larger figure. The
Gennadij [26K]
We have that
smaller figure
ha=8.7
ra=1.6

larger figure
hb=10.44
rb=1.92

ha/hb=8.7/10.44----> 0.83
ra/rb=1.6/1.92-------> 0.83

ratio smaller figure to the larger figure
1.6/1.92-------> divided by 1.6 both members
[1.6/1.6]/[1.92/1.6]-------> 1/1.2

the ratio ha/hb is equal to the ratio ra/rb
so
the smaller figure and the larger figure are similar
and the ratio smaller figure to the larger figure is equal to---->  1/1.2

the answer is
the option
yes 1/1.2
4 0
4 years ago
The median of Rae's data is 2.22 minutes, and the median of Doris' data is 2.14 minutes. The interquartile range for Rae is , an
JulsSmile [24]

Complete question :

Rae and Doris are training to swim a 200-meter freestyle race. The table lists their practice times during training camp.

Rae’s Times(minutes)-2.12, 2.01, 2.46, 2, 2.22, 2.31, 2.23

doris times(minutes)-2.32, 2.19, 2.26, 2.03, 2.11, 2.14, 2.07

The median of Raes data is(drop down box answers, 2,2.03,2.14,2.22)minutes,and the median of doris data is(drop down box answers, 2,2.03,2.14,2.22)minutes. The interquartile range for rae is(drop down box answers, 0.01,0.13,0.26,0.30), and the interquartile range for doris is(drop down box answers, 0.02,0.06,0.18,0.19). The two data sets overlap(drop down box answers,very little, a lot

Answer:

Rae's median = 2.22

Rae's IQR = 0.30

DORIS median = 2.14

Doris IQR = 0.19

Step-by-step explanation:

Given :

Rae's time :

Ordered data : 2, 2.01, 2.12, 2.22, 2.23, 2.31, 2.46

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.22

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.01

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.31

Interquartile range = Q3 - Q1 = 2.31 - 2.01 = 0.30

DORIS Data:

Ordered data: 2.03, 2.07, 2.11, 2.14, 2.19, 2.26, 2.32

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.14

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.07

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.26

Interquartile range = Q3 - Q1 = 2.26 - 2.07 = 0.19

6 0
3 years ago
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