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vredina [299]
3 years ago
9

8 - 14 + 95 - (-105) +(-111) - 63=? whats the answer?

Mathematics
2 answers:
Aliun [14]3 years ago
6 0
The answer is 20. When you go through the comments I said the steps are there.
Levart [38]3 years ago
3 0
Just do PEMDAS 
P: Parentheses 
\\ E:Exponents 
\\ M: Multiplication 
\\D: Division
\\ A: Addition
\\ S:Subtraction

So, we're doing Subtraction & Addition of this P
E
M
D
A
S

Now let's get this problem steps started

Step^1 : 8 - 14 + 95 = 89 
\\ Steo^2:  89 - (-105) = 194
\\ Step^3: 194 + (-111) = 83 \\ Step^4: 83 - 63 = 20 \\ Step^5: Answer:20

Remember: \\ +,+ = + \\ - , - = + \\ +, - = - \\ - , + = -

Good\\ luck \\ on \\ your \\ assignment

                                                            ~MeIsKaitlyn

Enjoy \\ your \\ day! :)
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\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }

Step-by-step explanation:

Hello, please find below my work.

2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0

\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}

Hope this helps.

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