8 - 14 + 95 - (-105) +(-111) - 63=? whats the answer?

Mathematics

2 answers:

Aliun [14]3 years ago

6 0

The answer is 20. When you go through the comments I said the steps are there.

Levart [38]3 years ago

3 0

Just do PEMDAS
$P: Parentheses 
\\ E:Exponents 
\\ M: Multiplication 
\\D: Division
\\ A: Addition
\\ S:Subtraction$

So, we're doing $Subtraction$ & $Addition$ of this $P
E
M
D
A
S$

Now let's get this problem steps started

$Step^1 : 8 - 14 + 95 = 89 
\\ Steo^2: 89 - (-105) = 194
\\ Step^3: 194 + (-111) = 83 \\ Step^4: 83 - 63 = 20 \\ Step^5: Answer:20$

$Remember: \\ +,+ = + \\ - , - = + \\ +, - = - \\ - , + = -$

$Good\\ luck \\ on \\ your \\ assignment$

~ $MeIsKaitlyn$

$Enjoy \\ your \\ day! :)$

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Compare the perimeter and area of the original figure to the perimeter and area of the reduced figure using the scale factor. A

Serggg [28]

Answer:

- The scale factor is one-half

- The perimeter of the model is the product of the scale factor and the perimeter of the original rectangle

-The area of the reduced figure is (1/2)^2 = 1/4 times the area of the original figure

Step-by-step explanation:

The ratio of the length of the original rectangle to that of the reduced rectangle is 6 to 3, or a factor of 1/2. The ratio of the width of the original rectangle to that of the reduced rectangle is 2 to 1, or, again, a factor of 1/2. So, because this ratio of 1/2 is constant, we know the total scale factor is 1/2, making B correct.

The perimeter of a rectangle is: $P=2l+2w$ , where l is the length and w is the width. The perimeter of the reduced figure is: P = 2 * 3 + 2 * 1 = 6 + 2 = 8 units. The perimeter of the original figure is: P = 2 * 6 + 2 * 2 = 12 + 4 = 16 units.

Notice that 16 * (1/2) = 8, which means that the perimeter of the scale-factored, reduced rectangle is "the product of the scale factor (which is 1/2) and the perimeter of the original rectangle (which is 16)". So, C is correct.

The area of a rectangle is: $A=lw$ , where l is the length and w is the width. The area of the reduced figure is: A = 3 * 1 = 3 units squared. The area of the original figure is: A = 6 * 2 = 12 units squared.