Minimize C = 6x + 3y Constraints: 4x + 3y > 24 4x + y = 16 6 x = 0, y

Hi guys sorri another one HEHHE I KINDA NEED THIS ASAP... THANKS YO SOMUCHHH

Ket [755]

Answer:

x = -1

Step-by-step explanation:

in pic

(Credits: Symbolab)

(Hope this helps can I pls have brainlist (crown)☺️)

6 0

2 years ago

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List an Order Pair from each of the 4 quadrants and tell which quadrant each point is in.

dexar [7]

( 1 ,2) is in first quadrant

(-1,2) is in second
(-1,-2) is in the third
( 1, -2) is in 4th quadrant

7 0

2 years ago

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Write the direct variation function given that y varies directly with x, and y = 1.5 when x = 5.

Cloud [144]

Answer:

y=0.3x

Step-by-step explanation:

Formula = $K=\frac{y}{x}$

y α x

y = kx

Where k is the constant of proportionality.

When y = 1.5; x = 5;

We substitute these known values in the equation,

y = kx

1.5 = k5

Dividing both sides of the equation by 5 to find the value for k, we have

1.5/5= k0.3/5

Therefore,

K = 0.3

Having found the value of k,

We substitute this value into the relationship

y = kx

Therefore we have,

y = 0.3x.

The direct variation function is therefore,

y = 0.3x.

[RevyBreeze]

4 0

2 years ago

A horse can run 1 3/8 of a mie in 1 3/5 minute. how long does it take the horse to run 1 mile

mario62 [17]

A horse can run 1 3/8 of a mile in 1 3/5 minute. How long does it take the horse to run 1 mile?

So what i would personally do first is convert the fractions into decimals.

1 3/8= 11/8= 1.375 of a mile

1 3/5= 8/5 =1.6 of a minute

Now we find the rate of change

I

8 0

2 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago

Minimize C = 6x + 3yConstraints: 4x + 3y > 244x + y = 166x = 0, y > 0​

Minimize C = 6x + 3yConstraints: 4x + 3y > 244x + y = 166x = 0, y > 0