What are the phase shift and period for the function y 3cos[4(0 + 459)]-4?

Mathematics

1 answer:

RUDIKE [14]3 years ago

3 0

I dont know the answer

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Find the illegal values of b in the fraction (2b^2+36-10)/(b^2-26-8)

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Correct Question is: Find the illegal values of b in the fraction (2b^2 + 3b - 10)/(b^2 - 2b - 8)

illegal values are those which are not a part of Domain. In this case these will be such values which will make the denominator of the fraction zero.

So setting the denominator equal to zero, we can find these values.

$b^{2} -2b-8=0 \\ \\ 
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b(b-4)+2(b-4)=0 \\ \\ 
(b+2)(b-4)=0 \\ \\ 
b=-2, b=4$

Thus, b=-2 and b=4 are the illegal values for this expression

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Nat2105 [25]

Answer:

Step-by-step explanation:

let me see if I can explain this...

3 + 5 = 8....those 2 numbers added together equals the total(8)...if u take the total(8) and subtract one of the numbers, it gives u the other number.

8 - 5 = 3 and 8 - 3 = 5

here's another one...

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100 - 30 = 60 and 100 - 60 = 30

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A researcher randomly selects 3 fish from among 8 fish in a tank and puts each of the 3 selected fish into different containers.

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First he can select one fish among 8, after that one among 7 of them and finally one among 6 fish.
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