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svlad2 [7]
3 years ago
13

I need HELP ON MY TEST 6+1 IS HELP

Mathematics
2 answers:
AleksandrR [38]3 years ago
6 0
7 i has to be it dose
sergeinik [125]3 years ago
4 0

Answer:

7..Bro you have to be trolling

Step-by-step explanation:

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Recall that Rn denotes the right-endpoint approximation using n rectangles, Ln denotes the left-endpoint approximation using n r
pogonyaev

Answer:

R_5=1.12

Step-by-step explanation:

We want to calculate the right-endpoint approximation (the right Riemann sum) for the function:

f(x)=x^2+x

On the interval [-1, 1] using five equal rectangles.

Find the width of each rectangle:

\displaystyle \Delta x=\frac{1-(-1)}{5}=\frac{2}{5}

List the <em>x-</em>coordinates starting with -1 and ending with 1 with increments of 2/5:

-1, -3/5, -1/5, 1/5, 3/5, 1.

Since we are find the right-hand approximation, we use the five coordinates on the right.

Evaluate the function for each value. This is shown in the table below.

Each area of each rectangle is its area (the <em>y-</em>value) times its width, which is a constant 2/5. Hence, the approximation for the area under the curve of the function <em>f(x)</em> over the interval [-1, 1] using five equal rectangles is:

\displaystyle R_5=\frac{2}{5}\left(-0.24+-0.16+0.24+0.96+2)= 1.12

3 0
2 years ago
Jack works at a sporting goods store and makes a commission of 20 percent. His sales for each week are shown below. How much did
kiruha [24]

Answer:

The answer is D

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The perimeter of a playing field for a certain sport is 214 ft. The field is a rectangle, and the length is 41 ft longer than th
malfutka [58]

Step-by-step explanation:

Perimeter of a rectangle = 2(L+W)

L is the length of the rectangle:

W is the width of the rectangle.

Given

Perimeter = 214feet

If the length is 41 ft longer than the width, then L = 41+W

Substitute L = 41+W into the formula:

P = 2(L+W)

214 = 2(41+W+W)

214 = 2(41+2W)

214 = 82+4W

4W = 214-82

4W = 132

W = 132/4

W = 33 feet

Since L = 41+W

L = 41+33

L = 74 feet

Hence the dimension of the field is 74ft by 33ft

<em>The width of the playing field is 33feet</em>

8 0
3 years ago
Karen karlin bought some large frames for $15 each and some small frames for $8 each at a closeout sale. if she bought 22 frames
BaLLatris [955]

small frames ($8): s

large frames ($15): L


Cost:        8s + 15L = 239   ⇒ 1(8s + 15L = 239)   ⇒    8s + 15L = 239  

Quantity:   s  +   L   = 22   ⇒  -8( s  +   L   = 22)   ⇒  <u> -8s   -8 L  = -176 </u>

                                                                                               7L  = 63

                                                                                                  L = 9

Quantity:   s + L = 22 ⇒   s + (9) = 22   ⇒   s = 13

Answer: 13 small frames, 9 Large frames

7 0
3 years ago
Read 2 more answers
Solve for x: 3+(-5)x=19
malfutka [58]
3+(-5)x=19
Subtract 3 from both sides of the equation.
-5x= 16
Divide by -5 on both sides
X= -3.2
4 0
3 years ago
Read 2 more answers
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