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Vesna [10]
3 years ago
12

Sharon was going through the financial records of her company. The profit earned by the company, p(t), over time t, in years, fo

r five consecutive years can be modeled by a quartic function. Each of the following functions is a different form of the quartic model for the situation given above. Which form would be most helpful if attempting to determine the time at the which the company did not earn any profit?
a.p(t) = 40(t - 3)(t + 2)(t - 5)(t + 3)


b.p(t) = 40(t2 - t - 6)(t2 - 2t - 15)


c.p(t) = 40t(t3 - 3t2 - 19t + 27) + 3,600


d.p(t) = 40t4 - 120t3 - 760t2 + 1,080t + 3,600
Mathematics
1 answer:
FromTheMoon [43]3 years ago
5 0
For this case what we must do is find a quadratic function that is already factored.
 This is because in the factored quadratic equations, it is easier to observe the zeros of the function.
 In this case, the zeros of the function represent the time at which the company did not make any profit.
 We have the following equation:
 p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
 We observed that there was no gain in:
 t = 3
 t = 5
 The other roots are discarded because they are negative
 Answer:
 
a.p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
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3 years ago
Select all pairs of numbers that have a least common multiple of 30.
ddd [48]

5 and 6  and 3 and 10, the pairs of numbers that have a least common multiple of 30.

<u>Step-by-step explanation:</u>

Case 1: LCM (3, 6)

Prime factorization of 3:  1 \times 3

Prime factorization of 6:  2 \times 3

Using all prime numbers found as often as each occurs most often we take

               2 \times 3=6

Therefore LCM (3, 6) = 6.

Case 2: LCM (5, 6)

Prime factorization of 5:  1 \times 5

Prime factorization of 6:  2 \times 3

Using all prime numbers found as often as each occurs most often we take

                     5 \times 2 \times 3=30

Therefore LCM (5, 6) = 30

Case 3: LCM (3, 10)

Prime factorization of 3:  1 \times 3

Prime factorization of 10:  2 \times 5

Using all prime numbers found as often as each occurs most often we take

                    5 \times 2 \times 3=30

Therefore LCM (3, 10) = 30

Case 4: LCM (5, 10)

Prime factorization of 5:  1 \times 5

Prime factorization of 10: 2 \times 5

Using all prime numbers found as often as each occurs most often we take

                       5 \times 2=10

Therefore LCM (5, 10) = 10

8 0
3 years ago
Two pitchers, Jerry and Louis, want to find out who has the faster pitch when compared to each of their teams. Jerry has a speed
saul85 [17]

Answer:

Louis has faster pitch when compared to each of their teams.

Step-by-step explanation:

We have two pitchers which we need to compare to each of their teams.

To calculate this, we will approximate the distributions to a normal distribution, and calculate the z-score, to know what proportion of players of their team fall below their score.

For Jerry, he has a speed of 86 and his team has a mean speed of 93 and standard deviation of 3.

We can calculate the z-score for Jerry speed as:

z=\dfrac{X-\mu}{\sigma}=\dfrac{86-93}{3}=\dfrac{-7}{3}= -2.333

The proportion of players that are below Jerry speed is approximated by the standard normal distribution:

p=\Phi(z

For Louis, his speed is 84 and his team has a mean speed of 89 and standard deviation of 3.5.

We can calculate the z-score for Jerry speed as:

z=\dfrac{X-\mu}{\sigma}=\dfrac{84-89}{3.5}=\dfrac{-5}{3.5}= -1.429

The proportion of players that are below Louis speed is approximated by the standard normal distribution:

p=\Phi(z

As the proportion of players of Louis team that are below Louis speed is much bigger than the proportion of players of Jerry's team that are below Jerry speed, we can say that Louis has faster pitch when compared to each of their teams.

6 0
3 years ago
When is the temperature constant?​
Colt1911 [192]

Answer:

The temperature is constant at 11 pm and remains constant until 2 pm.

7 0
3 years ago
Read 2 more answers
Jennifer scores a 77 on her algebra 2 test. The mean on the test was 73. The standard deviation on the test was 5. What was her
MA_775_DIABLO [31]

Answer:

  0.80

Step-by-step explanation:

The z-score is found from the formula ...

  Z = (X -μ)/σ

  Z = (77 -73)/5 = 4/5 = 0.80

Jennifer's Z-score was 0.80.

7 0
3 years ago
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