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Gala2k [10]
4 years ago
15

a cookie recipe calls for 5/8 cup of flour and 5/6 cup of sugar what is the least common denominator of the fractions A 6 B 12 C

18 D 24
Mathematics
2 answers:
iVinArrow [24]4 years ago
7 0
The answer is d becuase you have to find the least comman denominator


serious [3.7K]4 years ago
6 0
I think its 24 because 6*2 equals 12 but you cant multiply 8 by anything to get 12
with 24 6*4 equals 24 and 8*3 equals 24

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Which expression is equivalent to the given expression?<br> (3m-4) (375)
Brilliant_brown [7]

9514 1404 393

Answer:

  D.  81/m^7

Step-by-step explanation:

The applicable rules of exponents are ...

  (ab)^c = (a^c)(b^c)

  (a^b)^c = a^(bc)

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Using these, your expression simplifies to ...

  (3m^{-4})^3(3m^5)=(3^3)(3)(m^{-4\cdot3+5})=81m^{-7}=\boxed{\dfrac{81}{m^7}}

3 0
3 years ago
Help pls I don’t understand this my teacher didn’t teach this
aev [14]

Answer:

x = 60

Step-by-step explanation:

The tip of the triangle's angle is 100 (b/c 180-80)

x + 100 + 20 = 180

x + 120 = 180

x = 60

4 0
3 years ago
Read 2 more answers
Plot the points in the coordinate plane. Then find the perimeter and area of the polygon.
anyanavicka [17]

Answer:

The answer to your question is below

Step-by-step explanation:

See the graph below

Process

1.- Find the distance from A to B, B to C, C to D, A to D

Formula

d = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}

d AB = \sqrt{(1 + 3)^{2} + (6 - 5)^{2}}  = \sqrt{17}

dBC = \sqrt{(-2 -6)^{2} + (3 - 1)^{2}}  = \sqrt{68}

dCD = \sqrt{(-1 - 3)^{2} + (-3 +2)^{2}}  = \sqrt{17}

dAD = \sqrt{(-1 + 3)^{2} + (-3 - 5)^{2}}  = \sqrt{68}

2.- Find the perimeter

Perimeter = 2\sqrt{17} + 2\sqrt{68} = 6\sqrt{17} u

3.- Find the area

Area = \sqrt{17} x \sqrt{68}

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7 0
4 years ago
Combine like terms: x +x - x + y + y + y - z + z - z
Tomtit [17]
X  + x - x is   x
y + y + y is   3y
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x + 3y 
5 0
4 years ago
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

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x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

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(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
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