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spayn [35]
3 years ago
14

Oranges cost $ 1.53 for 3 pounds what is the ratio

Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

0.51

Step-by-step explanation:

since there are 3 pounds, we divide 1.53 by 3 to find the unit rate for one pound.

dividing 1.53 by 3 equals 0.51.

The answer is 0.51

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Please help me <br>is importe ​
astra-53 [7]

Answer:

A, B, C, D, E. there all greater than 2 and 5/6 because they all show 2 5/6 and they times somthing by that. Hope this helps! and maybe a Brainlest?

Step-by-step explanation:

7 0
3 years ago
Stanley runs, swims, and bikes every day. During these workouts, he runs at 9 mph, bikes at 16 mph, and swims at 2.5 mph. Yester
Maurinko [17]

The time spent for each activity can be found writing an equation based on

the known parameters.

  • The duration of the time Stanley spent running is <u>1.5 hours</u>
  • The duration of the time Stanley spent swimming is <u>1 hour</u>
  • The duration of the time Stanley spent Biking is <u>3 hours</u>

  • The distance Stanley cover while biking is <u>48 miles</u>

<u />

Reasons:

The running speed = 9 mph

The biking speed = 16 mph

Swimming speed = 2.5 mph

The time spent running = 0.5 hour + Time spent swimming

Biking time = 2 × Running time

The total distance covered = 64 miles

Required:

Time spent running, swimming, and biking

Solution:

Let <em>t</em> represent the time Stanley spent swimming, we have;

(t + 0.5)·9 + 2.5·t + 2×(t + 0.5)×16 = 64

43.5·t + 20.5 = 64

43.5·t  = 64 - 20.5 = 43.5

t = \dfrac{43.5}{43.5} = 1

  • The time Stanley spent swimming, t = <u>1 hour</u>

The time Stanley spent running = 0.5 + t

Therefore;

The time spent running = 0.5 hour + 1 hour = 1.5 hour

  • Time spent running = <u>1.5 hours</u>

Time spent biking = 2 × Running time

Therefore;

  • Time spent biking = 2 × 1.5 hours = <u>3 hours</u>

  • The distance Stanley cover while biking, d = 3 × 16 mph = <u>48 miles</u>

<u />

Learn more here:

brainly.com/question/23206880

7 0
3 years ago
in chemistry class Andrew has earned scores of 64 69 and 73 on three tests he must maintain an average of 72
olganol [36]
You haven't told me what the question is.  But I put the mouse
to my forehead, closed my eyes, took a deep breath, and I could
see it shimmering in my mind's eye.  It was quite fuzzy, but I think
the question is

                   "What score does Andrew need on the next test
                     in order to raise his average to 72% ?"

The whole experience drew an incredible amount of energy
out of me, and the mouse is a total wreck.  So we'll just go ahead
and answer that one.  I hope it's the correct question.

The average score on 4 tests is

                                     (1/4) (the sum of all the scores) .

In order for Andrew to have a 72% average on 4 tests,
the sum of the 4 scores must be

                                         (4) x (72%)  =  288% .

Out of that total that he needs, he already has 

                            (64% + 69% + 73%) = 206%

on the first three tests.

So in order to average 72% for all 4 tests,
he'll need to score

                             (288%  -  206%)  =   82%

on the fourth one.
6 0
3 years ago
HELP PLEASE PLEASE HELP, also show work!
7nadin3 [17]

Answer:

1 6 3b 0ny 5i bhk

Step-by-step explanation:

4 0
3 years ago
What is the slope for (0,1) and (3,0)
Dmitry [639]

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{0}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{0}}}\implies -\cfrac{1}{3}

5 0
3 years ago
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