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jek_recluse [69]
3 years ago
8

Bob is selling floral arrangements. Each arrangement uses 1 vase and 15 tulips. Each vase costs Bob $4.00. Let C be the total co

st of the arrangement and t be the cost of 1 tulip. Write an equation, in slope-intercept form, that represents the total cost of each arrangement to Bob. Use this equation to find out what the cost of the arrangement would be if each tulip costs Bob $2.00.
Mathematics
1 answer:
Masja [62]3 years ago
3 0
<span>slope-intercept form is y = mx + b 

the question is asking what the cost is to Bob. So, y = cost to Bob 
Each arrangement has only one vase making it a constant. b = vase

At the moment y = mx + b in terms of this problem is... 
the cost to Bob = number of flowers(cost of one flower) + cost of a vase 

When plugging in and solving the equation looks like 
y = 15(2) + 4 
                 where y = 34</span>
You might be interested in
how can you use the sine and cosine ratios and their inverses in calculations involving right triangles
Marysya12 [62]

Answer:

Step-by-step explanation:

I will show you by example.  For the sin ratio, we have that the sin of the reference angle is equal to the side opposite the angle over the hypotenuse of the right triangle.  We use this example for finding the ratio, knowing the angle:

sin(60)=.866025 found on your calculator.  Because this is a special angle in a right triangle, we can also say, by looking at a 60 degree reference angle that the side across from the angle measures square root of 3, and the hypotenuse measures 2.  So in terms of a radical,

sin(60)=\frac{\sqrt{3} }{2}

If we don't know the angle, we use the 2nd button on our calculator to find it.  For example, if our problem looked like this:

sin\theta=\frac{1}{2},

we are asked what angle has a sin ratio of 1/2.  We find this angle by pressing the 2nd button on our calculator, then the sin button and you will see this on your screen:

sin^{-1}(

Enter either a .5 or a 1/2 after that open parenthesis and hit enter and you'll get the angle measure.  That's how you use the inverses to solve for missing angles.

3 0
3 years ago
An airplane leaves an airport at 9:00 p.M. With a heading of 270 and a speed of 610 mph. At 10:00 p.M. The pilot changes the he
timama [110]

Answer:

2330.51 miles

Step-by-step explanation:

Given that the speed of the airplane = 610 mph.

The airplane leaves an airport at 9:00 P.M. with a heading of 270 degrees and at 10:00 P.M., the pilot changes the heading to 310 degrees.

So, for 1 hour the plane is heading at 270 degrees and for 3 hours, from 10:00 p.m to 1:00 a.m, the plane is heading at 310 degrees as shown in the figure.

As, distance = time x speed, so

The distance covered at 270 degrees, d_1 = 1\times610=610 miles.

The distance covered at 310 degrees, d_2 = 3\times610=1830 miles.

Total distance covered, d, is the magnitude of the sum of vectors \vec{d_1} and \vec{d_2} as shown in the figure.

The angle between the vectors \vec{d_1} and \vec{d_2}, \theta=310-270=40 degree.

Magnitude of sum of the vectors \vec{d_1} and \vec{d_2},

d= \sqrt{|\vec{d_1}|^2+|\vec{d_2}|^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\theta} \\\\\Rightarrow d=\sqrt{610^2+1830^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\(40^{\circ})}

\Rightarrow d=2330.51 miles

Hence, at 1:00 a.m, the airplane is at a distance of 2330.51 miles from the airport.

4 0
3 years ago
One of the zookeepers solved to find Bernard’s speed when he is healthy using the equation:
MrRissso [65]

Answer:

Both the zoo-keepers are correct.

Step-by-step explanation:

The first zoo keeper uses the equation:

x - 41.5 = 13.5

⇒ x = 13.5 + 14. 5 = 55

Now, the second zoo- keeper uses the equation:

41.5 + 13.5 = x

⇒ x = 55

Both use x = 55.

4 0
3 years ago
Read 2 more answers
The manager of a dress shop recorded the number of dresses sold during the week the data is as follows
Rashid [163]
2.6925 is the mean/ avg you add all the numbers and divide by the amount of numbers you added
5 0
3 years ago
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
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