Answer:
m=3/4
Step-by-step explanation:
first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)
we have the equation 4x+3y=9
subtract 4x from both sides
3y=-4x+9
divide by 3
y=-4/3x+3
perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1
so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1
(m is the slope value)
-4/3m=-1
multiply by -3/4
m=3/4
therefore the slope of the perpendicular line is 3/4
hope this helps!! :)
The answer is the first option, you multiply 14^2 by 9
<u>Given</u><u> </u><u>info:</u><u>-</u>If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height.
Find the ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder ?
<u>Explanation</u><u>:</u><u>-</u>
Let the radius of the right circular cylinder be r units
Let the radius of the right circular cylinder be h units
Curved Surface Area of the original right circular cylinder = 2πrh sq.units ----(i)
If the radius of the right circular cylinder is doubled then the radius of the new cylinder = 2r units
The height of the new right circular cylinder
= (1/4)×h units
⇛ h/4 units
Curved Surface Area of the new cylinder
= 2π(2r)(h/4) sq.units
⇛ 4πrh/4 sq.units
⇛ πrh sq.units --------(ii)
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder
⇛ πrh : 2πrh
⇛ πrh / 2πrh
⇛ 1/2
⇛ 1:2
Therefore the ratio = 1:2
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder is 1:2
Answer:
The answer to the question provided is 14.
Step-by-step explanation:
》The Distance Formula:

》Plug in.

The intervals on which the graph is increasing: ]-∞,-3[ U ]0.5,-∞[ . On the other hand, the graph is decreasing: ]-3,0.5[
<h3>Function</h3>
A function can be classified as increasing or decreasing. Thus, a function is increasing when the y-values increase, on the other hand, a function is decreasing when the y-values decrease.
From the image, you can see that the y-values increase in the following x-intervals: from -∞ to -3 and from 0.5 to ∞. Using interval notation, you can write that the function is increasing in:
]-∞,-3[ U ]0.5,-∞[
From the graph, you can see that the y-values decrease in the following x-intervals: from -3 to 0.5. Using interval notation, you can write that the function is decreasing in:
]-3,0.5[
Learn more about function here:
brainly.com/question/2649645