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dolphi86 [110]
3 years ago
12

Hat is the product of 4.01 × 10-5 and 2.56 ×108?

Mathematics
2 answers:
ASHA 777 [7]3 years ago
7 0

Answer:

35.1 and 276.48

Step-by-step explanation:

DIA [1.3K]3 years ago
5 0

Answer:

The correct answer is: 1.0266 ×104

Step-by-step explanation:

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Im having a hard time on edge any tips?
slamgirl [31]

Answer:

Take deep breaths and focus, don't be afraid to ask for help.

Good luck!

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In ΔTUV, t = 560 inches, v = 400 inches and ∠V=19°. Find all possible values of ∠T, to the nearest degree
Serjik [45]

Answer:

27 and 153 degrees

Step-by-step explanation:

Delta math

6 0
2 years ago
Mahra saw an ad for three t-shirts for $33 and four t-shirts costing $42. Is the relationship of price and number of t-shirts a
slamgirl [31]

Answer

no  because as per the first ad the rate of a shirt is 11 dollars wherelse if u take second one its 2 dollars lesser

Step-by-step explanation:

1 shirt=33/3

=11

11*4=44

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4 0
3 years ago
Ravi will take the 6:37 PM train to San Diego. The train is estimated to arrive in San Diego in 3 hours 45 minutes. What is the
Ahat [919]
So 6+3 is 9 right? So let's just say it's 9:37 with a 45 min ride. 60 minutes are in a hour. 60 - 37 = 23. We have 23 minutes left until 10:00. 45- 23 = 22. Therefore it'd be 10:22 p.m.
7 0
3 years ago
At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
wolverine [178]

Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

  • Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
  • Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
  • Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
  • Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0
3 years ago
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