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3 years ago

Simplify The Equation

Mathematics

1 answer:

statuscvo [17]3 years ago

4 0

Answer:

Step-by-step explanation:

5 ^ 1/3 * 25 ^ 1/3

Rewriting 25 and 5^2

5 ^ 1/3 * 5^2 ^ 1/3

We know that a^b^c = a^ (b*c)

5 ^ 1/3 * 5^ 2/3

We know a^b * a^c = a^(b+c)

5^ ( 1/3 + 2/3)

5^1

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A motorcycle that regularly sells for 1,450 was discounted by 40% off

marissa [1.9K]

Answer:

$870.00 is the motorcycle price after a 40% discount

Step-by-step explanation:

discount = original price x discount % / 100

discount = 1450 x 40 / 100

discount = 1450 x 0.4

<u>discount = $580.00</u>

Final Price = Original Price - Discount

Final Price = 1450 - 580

<u>Final Price = $870</u>

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2 years ago

What is the area of the sector?

xeze [42]

Area of the sector is 981.3 cm²

Step-by-step explanation:

Step 1: Find the area of the sector where radius = 50 cm and central angle = 45°

Area of the sector = πr² (C/360), where r is radius and C is the central angle

⇒ Area = 3.14 × 50² × (45/360)

= 3.14 × 2500 × 1/8

= 7850/8 = 981.3 cm²

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3 years ago

160% of what number is 19.2

riadik2000 [5.3K]

Answer:

The number is 12

Step-by-step explanation:

Let x be the number

160/100 = 1.6

1.6 x = 19.2

x = 19.2 / 1.6

x = 12

7 0

3 years ago

HELP PLEASE!!!!!!! BRAINLIEST REWARD IS UP!!! CORRECT ANSWER ONLY PLEASE!!!

Mashcka [7]

B: exponential; y=3^x-1

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4 years ago

A pathologist has been studying the frequency of bacterial colonies within the field of a microscope using samples of throat cul

nata0808 [166]

Answer:

P(0) = 0.055

P(1) = 0.16

P(2) = 0.231

P(3) = 0.224

P(4) = 0.162

P(5 or more) = 0.168

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Here λ = 2.90 is the average number of bacteria colonies per field.

This means that $\mu = 2.90$

Compute P(r) for r = 0, 1, 2, 3, 4, and 5 or more.

$P(0) = \frac{e^{-2.9}*(2.9)^{0}}{(0)!} = 0.055$

$P(1) = \frac{e^{-2.9}*(2.9)^{1}}{(1)!} = 0.16$

$P(2) = \frac{e^{-2.9}*(2.9)^{2}}{(2)!} = 0.231$

$P(3) = \frac{e^{-2.9}*(2.9)^{3}}{(3)!} = 0.224$

$P(4) = \frac{e^{-2.9}*(2.9)^{4}}{(4)!} = 0.162$

5 or more:

This is

$P(X \geq 5) - 1 - P(X < 5)$

In which:

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.055 + 0.16 + 0.231 + 0.224 + 0.162 = 0.832$

$P(X \geq 5) - 1 - P(X < 5) = 1 - 0.832 = 0.168$

P(5 or more) = 0.168

7 0

3 years ago