Answer:
Step-by-step explanation:
a) you know interest is 22 and principal is 1000 and number of months is 1
b) I = rPm
r = I/Pm
c) r = 22 / 1000(1) = 0.022 /month or 2.2% per month
or 12(0.022) = 0.264 or 26.4 % per year.
d) interest is $15, loan period is 2 weeks which occurs once during the loan, interest rate is 10% per two weeks.
P = I/rm
e) P = 15 / 0.10 = $150
Notice that there are 52 weeks/yr / 2week loan period = 26 period in a year.
This means that the APR is 0.10(26) = 2.60 or 260% annual interest rate. Pretty good return on investment if you are the lender and can keep your money lent out. Not so good if you are the borrower.
Volume of a cube is sides a3
so 10x10x10
V=1000cm
A. Judy made a mistake between Steps 1 and 2
To factor
, you have to factor it as
, not
, because that will leave an extra 6x because of 8x - 2x.
The diagonals of a parallelogram bisect each other so
4x - 7 = x + 2 and
5y - 8 = 3y
4x - 7 = x + 2 so 3x = 9 and x = 3
5y - 8 = 3y so 2y = 8 and y = 4
Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.
Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:
The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.
Thus, the lowest score of test A is given by 40(21) + 50 = 890
Therefore, the lowest score of test A is 890.
Part B:
The mean score is a measure of location, so both
addition and multiplying the mean score of test B by 40 and adding 50
to the result will affect the lowest score of test A.
Thus, the mean score of test A is given by 40(29) + 50 = 1,210
Therefore, the mean score of test A is 890.
Part C:
The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50
to the result will not affect the standard deviation of test A.
Thus, the standard deviation of test A is given by 40(2) = 80
Therefore, the standard deviation of test A is 80.
Part D
The Q3 score is a measure of location, so both
addition and multiplying the Q3 score of test B by 40 and adding 50
to the result will affect the Q3 score of test A.
Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170
Therefore, the Q3 score of test a is 1,170.
Part E:
The median score is a measure of location, so both
addition and multiplying the median score of test B by 40 and adding 50
to the result will affect the median score of test A.
Thus, the median score of test A is given by 40(26) + 50 = 1,090
Therefore, the median score of test A is 1,090.
Part F:
The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50
to the result will not affect the IQR of test A.
Thus, the IQR of test A is given by 40(6) = 240
Therefore, the IQR of test A is 240.
