<img src="https://tex.z-dn.net/?f=100000%20%5Ctimes%207000%20%2B%200" id="TexFormula1" title="100000 \times 7000 + 0" alt="10000

Jimmy invests $7,000 in an account that pays 3% interest compounded semi-annually. What is his balance after 8 years?

Bumek [7]

Answer:

$8882.9

Step-by-step explanation:

A=p(1+(r/n))^nt

Given:P=7000, r=(3÷100%)=0.03 , n=2, t=8

A = 7000(1+(.03/2))^(2×8)

A = 7000 (1+0.015)^16

A = 7000 × 1.015^16

A = $8882.9

7 0

2 years ago

App 19.study

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

3 years ago

1 1/3 x 5/8 A.3/4 B.4/5 C.5/6 D.5/8

Dmitriy789 [7]

The answer is 5/6, hope this helps

5 0

2 years ago

Read 2 more answers

a language arts test is worth 100 points there is a total of 26 questions . there are spelling word questions that ae worth 2 po

natka813 [3]

10 question of spelling words and 16 questions of vocabulary are present

Solution:

Let "x" be the number of spelling word questions

Let "y" be the number of vocabulary word question

There is a total of 26 questions. Therefore, we get

number of spelling word questions + number of vocabulary word question = 26

x + y = 26 --------- eqn 1

There are spelling word questions that worth 2 points each and vocabulary word question worth 5 points each

The language arts test is worth 100 points

Therefore, we frame a equation as:

number of spelling word questions x 2 + number of vocabulary word question x 5 = 100

$x \times 2 + y \times 5 = 100$

2x + 5y = 100 --------- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

x = 26 - y ------- eqn 3

Substitute eqn 3 in eqn 2

2(26 - y) + 5y = 100

52 - 2y + 5y = 100

3y = 100 - 52

3y = 48

Substitute y = 16 in eqn 3

x = 26 - 16

Thus 10 question of spelling words and 16 questions of vocabulary are present

4 0

2 years ago

Find three consecutive integers whose sum is equal to −354. Three consecutive integers in ascending form are __,__,__

mixer [17]

Answer: -119, -120, and -121

Step-by-step explanation: This problem states that the sum of three consecutive integers is -354 and it asks us to find the integers. Three consecutive integers can be represented as followed.

X ⇒ first integer

X + 1 ⇒ second integer

X + 2 ⇒ third integer

Since the sum of our three consecutive integers is -354, we can set up an equation to represent this.

X + X + 1 + X + 2 = -354

Now, we can simplify on the left side of the equation.

3x + 3 = -354

-3 -3 ← subtract 3 on both sides of the equation

3x = -357

÷3 ÷3 ← divide both sides by 3

X = -119

X ⇒ first integer = -119

X + 1 ⇒ second integer = -120

X + 2 ⇒ third integer = -121

Therefore, our three consecutive integers are -119, -120, and -121.

6 0

3 years ago

Read 2 more answers