Answer:
12 windows
Step-by-step explanation:
Number of windows broken = 40% of 30

I think 2 equal ratios are called a <u>proportion</u>
Answer:
○ 
Step-by-step explanation:
3 → 13 − 16
![\displaystyle \frac{Number\:of\:desired\:[favourable]\:outcomes}{Total\:number\:of\:possible\:outcomes} \\ \\ \frac{3}{12} = \frac{1}{4} = 25\%](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BNumber%5C%3Aof%5C%3Adesired%5C%3A%5Bfavourable%5D%5C%3Aoutcomes%7D%7BTotal%5C%3Anumber%5C%3Aof%5C%3Apossible%5C%3Aoutcomes%7D%20%5C%5C%20%5C%5C%20%5Cfrac%7B3%7D%7B12%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D%20%3D%2025%5C%25)
I am joyous to assist you anytime.
The best option is the first one (Six yards of rope costs $5.50). It is the lowest unit cost.
<u>Step-by-step explanation:</u>
For the given question case, first we should compare the unit costs of the choices provided and evaluate the best option.
Choice 1:
Six yards of rope costs $ 5.50

Choice 2:
Four yards costs $ 4.75

Thus, the best choice is the first one. Because it is the lowest unit cost.
Answer:
Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and
respectively.
Step-by-step explanation:
Given that,
For the first 9 holes X:
E(X) = 80
SD(X)=13
For the second 9 holes Y:
E(Y) = 80
SD(Y)=13
For the sum W=X+Y, the following properties holds for means , variance and standard deviation :
E(W)=E(X)+E(Y)
and
V(W)=V(X)+V(Y)
⇒SD²(W)=SD²(X)+SD²(Y) [ Variance = (standard deviation)²]

∴E(W)=E(X)+E(Y) = 80 +80=160
and
∴



Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and
respectively.