Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
81
Step-by-step explanation:
2x+6=84
2x=78
81
find your own way
B) 2 (5 + 7) = 2 × 5 + 2 × 7
Distributing the two multiples the five and seven and adds there them together.
2464829438
The next number is 2,464,829,439
Answer:
:)
Step-by-step explanation:
9 & 10
go add the snap carmel.bratz
