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3 years ago

Find the sum 45+46+47+48+...+129+130

Mathematics

1 answer:

Leno4ka [110]3 years ago

6 0

Use photo math to help you with this question

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1. Which of the following are NOT triangle congruence postulates? (There may be more than one answer.)

andreev551 [17]

Answer:

a)Angle Angle Angle

d)Angle Side Side

f)Side Side Angle

Step-by-step explanation:

The postulates that are used to prove the triangles congruent are:

1)Side Side Side

2)Side Angle Side

3)Angle side Angle

4)Angle Angle Side

5)Hypotenuse Leg

Other than these postulates none can be used to prove the triangles congruent.

The choices which are not triangle congruence postulate are:

a)Angle Angle Angle

d)Angle Side Side

f)Side Side Angle

3 0

3 years ago

What’s 5000÷4x8÷3x20?

PilotLPTM [1.2K]

Answer:

1250 3 x28

Step-by-step explanation:

5000

x20

4 0

3 years ago

Read 2 more answers

(x/x+3)-(8/x+2)=(-13x-6)/(x^2+5x+6)

Fed [463]

Answer:

x = -9

x = 2

Step-by-step explanation:

Given:

$\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{x^2+5x+6}$

First, note that

$x^2+5x+6=x^2+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)$

Since $x+2$ and $x+3$ stay in the denominator, then

$x\neq -2\ \text{and}\ x\neq -3$

Now add two fractions which stay in the left part. The common denominator is $(x+2)(x+3),$ so multiply the numerator of the first fraction by $(x+2)$ and the numerator of the second fraction by $(x+3)$ and subtract them in the numerator:

$\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\\dfrac{x(x+2)-8(x+3)}{(x+2)(x+3)}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\x(x+2)-8(x+3)=-13x-6\\ \\x^2+2x-8x-24=-13x-6\\ \\x^2+2x-8x+13x-24+6=0\\ \\x^2+7x-18=0\\ \\x^2+9x-2x-18=0\\ \\x(x+9)-2(x+9)=0\\ \\(x+9)(x-2)=0\\ \\x+9=0\ \text{or}\ x-2=0\\ \\x=-9\ \text{or}\ x=2$