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2 years ago

Carmen has 75% less money than Anna. How much money does Carmen have if Anna has 256?

Mathematics

1 answer:

Lady_Fox [76]2 years ago

6 0

Answer:

$64

Step-by-step explanation:

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What is the m GE bisects Find m

nirvana33 [79]

Answer:

DGF = 106

Step-by-step explanation:

Bisects means to divide in half, with two equal parts

DGF = DGE + EGF

DGE = EGF

DGF = DGE + DGE

DGF = 53+53

DGF = 106

8 0

2 years ago

Read 2 more answers

I will mark you brainiest if you can answer this

Vikentia [17]

7 will never equal 8 so there is no solution. so i think it is C

3 0

2 years ago

Kate Alexander worked 40 hours last week. Her pay rate is $8.50 per hour. Assuming 7.65% social security withholding, how much s

Andrej [43]

40 x 8.50 = 340
340 x .0765 = 26.01

So the employer should withhold $26.01 from her check for social security.

8 0

2 years ago

Let g(x) = 2x and h(x) = x^2 + 4. Find the value.(g o h) (0)a) 4b) 8c) 0d) 16

Paul [167]

$\begin{gathered} \text{Given} \\ g(x)=2x \\ h(x)=x^2+4 \end{gathered}$

Solve for (g o h)(x)

$\begin{gathered} (g\circ f)(x)=g\big(f(x)\big) \\ (g\circ f)(x)=g(x^2+4) \\ (g\circ f)(x)=2(x^2+4) \\ (g\circ f)(x)=2x^2+8 \end{gathered}$

Next substitute x = 0

$\begin{gathered} (g\circ f)(x)=2x^2+8 \\ (g\circ f)(0)=2(0)^2+8 \\ (g\circ f)(0)=8 \end{gathered}$ $\text{Therefore, }(g\circ f)(0)=8$

5 0

1 year ago

Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0

guajiro [1.7K]

Answer:

$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

$\displaystyle -3x^4+27x^2+1200=0$

If we call $y=x^2$ , our equation becomes a second-degree equation

$\displaystyle -3y^2+27y+1200=0$

Dividing by -3

$\displaystyle y^2-9y-400=0$

Factoring

$\displaystyle (y-25)(y+16)=0$

It leads to these solutions

$\displaystyle y=25\ ,\ y=-16$

Taking back the change of variable, we have for the first solution

$\displaystyle x^2=25\Rightarrow x=-5,x=5$

Now for the second solution, we get imaginary (complex) values

$\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i$

Summarizing, the four solutions for x are

$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

5 0

2 years ago