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elixir [45]
2 years ago
13

HELP PLEASE , I NEED THIS DUE IN 10 MINUTES AND IM SO CONFUSED

Mathematics
1 answer:
UNO [17]2 years ago
8 0

Answer:

p+37 = 2p-50

87

m<I=124

Step-by-step explanation:

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The diagram shows a hexagon-shaped tile used for flooring. Each hexagon tile has an area of 18/3 in 2 Find x.​
mylen [45]

Answer:

x = 12

Step-by-step explanation:

The hexagonal tile given here is made up of 6 triangles with equal bases and heights.

So, area of hexagonal tile will be equal to 6 times the area of one triangle.

Therefore,

18 \sqrt{3}  = 6 \times  \frac{1}{2}  \times 2 {( \sqrt{3)} }^{ \frac{x}{12} } . {( \sqrt{3)} }^{ \frac{x}{6} }  \\  \\ 18 \sqrt{3}  = 6  {( \sqrt{3)} }^{ \frac{x}{12} } . {( \sqrt{3)} }^{ \frac{2x}{12} }  \\  \\  \frac{18 \sqrt{3}  }{6}  = {( \sqrt{3)} }^{ \frac{x}{12}  +  \frac{2x}{12} }  \\  \\ 3 \sqrt{3}  =  {( \sqrt{3)} }^{ \frac{3x}{12} } \\  \\ 3. {3}^{ \frac{1}{2} }  =  {3}^{ \frac{3x}{24} }  \\  \\  {3}^{1 +  \frac{1}{2} }  =  {3}^{ \frac{x}{8} }  \\  \\ {3}^{ \frac{3}{2} }  =  {3}^{ \frac{x}{8} }  \\ (bases \: are \: equal \: so \: exponents \:  \\ will \: also \: be \: equal) \\ \implies  \frac{3}{2}  =  \frac{x}{8}  \\  \\ x =  \frac{3 \times 8}{2}  \\  \\ x = 3 \times 4 \\  \\ x = 12

7 0
2 years ago
Read 2 more answers
Evaluate the following expression when x = 3 and y = 4: Fraction with x squared plus y cubed in the numerator and 2 plus x in th
Black_prince [1.1K]
The answer is C. 14.6.

By evaluate, they mean substitute in the values of x and y to find the total of the expression, so you get:
(3^2 + 4^3)/(3 + 2) = (9 + 64)/5 = 73/5 = 14.6

I hope this helps!
4 0
3 years ago
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Find the equation of the parabola with its focus at (6,2) and its directrix y = 0. Question 17 options: A) y = –1∕4(x – 6)2 + 1
Law Incorporation [45]
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8 0
3 years ago
Values of k for which the quadratic equation 2x - kx + k 0 has equal roots is
WARRIOR [948]

Answer:

The answer is D.

Step-by-step explanation:

We have to apply Discriminant Law. When a quadratic equation, ax² + bx + c = 0 has equal roots so the discriminant will be 0. Then, you have to substitute the values into the formula :

D =  {b}^{2}  - 4ac

let   \: D = 0 ,a = 2,b = k,c = k

0 =  {k}^{2}  - 4(2)(k)

{k}^{2}  - 8k = 0

k(k - 8) = 0

k = 0

k - 8 = 0

k = 8

4 0
3 years ago
Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}
Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

<h3>   </h3>
  • To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by \large \sf a^{n}. The terms of a power are:

<h3>     </h3>
  • Base
  • Exponent
  • equal factors
  • power
<h3>         </h3>

✏️ <u>Resolution/Answer</u>:

\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\

  • Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4\cdot4}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=\\\\

  • <em>Multiply </em>the power at denominator of the fraction:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4\cdot4}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=\\\\

  • <em>Multiply </em>the numerator numbers together:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=

\large \sf \dfrac{-16\cdot16\cdot 256     }{16}=

\large \sf \dfrac{-256\cdot 256     }{16}=

\large \sf \dfrac{- 65536  }{16}=\\\\

  • Simplify the fraction by number 16:

\\\large \sf \dfrac{- 65536  }{16}=

\large \sf \dfrac{- 65536  \div16}{16\div16}=

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}} \\\\\\

  • So this expression in its simplified form = -4096/1 or -4096.

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}}\\\\

                                 ★ Hope this helps! ❤️

6 0
2 years ago
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