Answer:
3rd option: B(C)= 1.79C +86.03
Step-by-step explanation:
Total bill
= cost of cans(number of cans) +cost of other groceries
Let the cost of other groceries be G, and the cost of cans be X.
Given that number of cans= C,
Total bill= XC +G
If 2 cans were purchased,
2X+G= 89.61 -----(1)
If 5 cans were purchased,
5X +G= 94.98 -----(2)
(2) -(1):
(5X +G) -(2X +G)= 94.98 -89.61
5X +G -2x -G= 5.37
3X= 5.37
X= 5.37 ÷3 <em>(</em><em>÷</em><em>3</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
X= 1.79
Subst. X= 1.79 into (1):
2(1.79) +G= 89.61
3.58 +G= 89.61
G= 89.61 -3.58 <em>(</em><em>-3.58</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
G= 86.03 <em>(</em><em>simplify</em><em>)</em>
Total bill
= XC +G
= 1.79C +86.03
Thus, the function is B(C)= 1.79C +86.03.
Answer:
Rhombus
Step-by-step explanation:
The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).
We use the distance formula to find the length of AB.
![|AB|=\sqrt{(-1--5)^2+(8-6)^2}](https://tex.z-dn.net/?f=%7CAB%7C%3D%5Csqrt%7B%28-1--5%29%5E2%2B%288-6%29%5E2%7D)
![|AB|=\sqrt{16+4}](https://tex.z-dn.net/?f=%7CAB%7C%3D%5Csqrt%7B16%2B4%7D)
![|AB|=\sqrt{20}](https://tex.z-dn.net/?f=%7CAB%7C%3D%5Csqrt%7B20%7D)
The length of AD is
![|AD|=\sqrt{(-1--5)^2+(6-4)^2}](https://tex.z-dn.net/?f=%7CAD%7C%3D%5Csqrt%7B%28-1--5%29%5E2%2B%286-4%29%5E2%7D)
![|AD|=\sqrt{16+4}](https://tex.z-dn.net/?f=%7CAD%7C%3D%5Csqrt%7B16%2B4%7D)
![|AD|=\sqrt{20}](https://tex.z-dn.net/?f=%7CAD%7C%3D%5Csqrt%7B20%7D)
The length of BC is:
![|BC|=\sqrt{(-1-3)^2+(8-6)^2}](https://tex.z-dn.net/?f=%7CBC%7C%3D%5Csqrt%7B%28-1-3%29%5E2%2B%288-6%29%5E2%7D)
![|BC|=\sqrt{16+4}](https://tex.z-dn.net/?f=%7CBC%7C%3D%5Csqrt%7B16%2B4%7D)
![|BC|=\sqrt{20}](https://tex.z-dn.net/?f=%7CBC%7C%3D%5Csqrt%7B20%7D)
The length of CD is
![|CD|=\sqrt{(-1-3)^2+(6-4)^2}](https://tex.z-dn.net/?f=%7CCD%7C%3D%5Csqrt%7B%28-1-3%29%5E2%2B%286-4%29%5E2%7D)
![|CD|=\sqrt{16+4}](https://tex.z-dn.net/?f=%7CCD%7C%3D%5Csqrt%7B16%2B4%7D)
![|CD|=\sqrt{20}](https://tex.z-dn.net/?f=%7CCD%7C%3D%5Csqrt%7B20%7D)
Since all sides are congruent the quadrilateral could be a rhombus or a square.
Slope of AB![=\frac{8-6}{-1--5}=\frac{1}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B8-6%7D%7B-1--5%7D%3D%5Cfrac%7B1%7D%7B2%7D)
Slope of BC ![=\frac{8-6}{-1-3}=-\frac{1}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B8-6%7D%7B-1-3%7D%3D-%5Cfrac%7B1%7D%7B2%7D)
Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus
Answer: (8, -13)
Step-by-step explanation:
-2 is 5 away from 3, and 9 is 11 away from -2. so add 5 to 3 which is 8, and add -11 to -2 which is -13.
5+3=8 (x)
-11+(-2)=-13 (y)
There for the correct answer is (8, -13) when (x, y).
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Answer:
y=83333728267=९%--#7*$-#-4-!