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Bess [88]
2 years ago
9

Yea yea you know i need help my brains tiny thank you for everything and everyone helping

Mathematics
2 answers:
Darina [25.2K]2 years ago
4 0

Answer: r=6

Step-by-step explanation:

<u>Step 1: Substitute for the known variables</u>

we know that the formula to find the volume of a cylinder is <u>V= πr²h</u>

π= 3.14

h= 12

r= ?

v=1,357

Plugging the numbers we know into the formula, we get:

1,357= 3.14xr²x12

1,357= 3.14x12xr² (because with the commutative property of multiplication you can multiply in any order)

1,357= 37.68 x r²

<u>Step 2: Get the variable term (the letter term) on the left</u>

37.68 x r²= 1,357

Now, divide by 37.68. (I know to divide because when you switch the 37.68x r² the other way around to  r²x37.68, you are clearly multiplying and must do the inverse operation (opposite of multiplication; division) to solve the problem.

So,

r²= 1357÷37.68

r²= 36.0138004 ----> about 36.

r²= 36

This equation isn't over yet because we still have the exponent on the r. Whenever you see a letter squared (to the power 2) in an equation, the "inverse operation" is to take the square root of both sides. Look:

r²= 36

The square root of  r² is just r, because r x r =  r²

The square root of 36 is 6, because 6x6=36.

Now we have :

r= 6

Step 3: Check

Now we have all the variables. To check to make sure the radius is correct, "plug in"

V= π r²h

1,357= 3.14x6²x12

1,357= 3.14x36x12

1,357= 113.04x12

1,357= 1356.48

They said in the question that the volume is APPROXIMATLEY 1357, so I can just round 1356.48 --> 1356.5---> 1357. Now I am sure that the radius is 6.

Hope this helps :)) also brainliest would be appreciated  :D

Anni [7]2 years ago
4 0
Answer r=6 I won’t put you through the reading
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Please, do not present a long list of questions like this without either explanation of what kind of help you need or what you have already done. One or two problems per post is the informal limit.


I will do just the first problem for you, to get you started, and ask you to share your efforts on the next one.



x-3y≥6

-5x-3y≥-6


We are to find values of both x and y such that points (x,y) satisfy both constraints


x-3y≥6

-5x-3y≥-6.


For simplicity's sake, replace the " ≥ " sign with " = " as follows:


x-3y = 6

-5x-3y= -6


Let's solve this system thru elimination. Mult. the 2nd eqn by -1 to change the sign of all its terms:



5x + 3y = 6


and then add this result to the 1st equation:


5x + 3y = 6

x-3y = 6

-------------------

6x = 12, so x = 6. Now subst. 6 for x in x-3y = 6: 6-3y = 6. Thus, y=0.


The point at which the 2 lines cross is (6,0).


Graph both lines, using solid (not broken) lines, due to the " = " in " ≥ .


Because of the " ≥ " signs in each of the original inequalities, shade the graph ABOVE each of these solid lines. Note that you will have TWO shaded areas, which partially overlap. The solution set here is represented by the area that has been shaded twice.


To help you with the graphing:


x-3y = 6 can be rewritten as 3y = -x + 6, or y = (-1/3)x + 2. This line has a y-intercept of 2 and a slope of -1/3.


-5x-3y≥-6 can be rewritten as - 3y = 5x - 6, or y = (-5/3)x + 2. This line has a y-intercept of 2 (same as the other line) and a slope of -1/3 (different from the other one).


If you do this graphing correctly, you will find that the 2 lines intersect at (6,0).


The most efficient way to show the "solution" of this system of inequalities is to graph the two lines and shade the areas above them. Draw lines around the area that has been shaded twice.


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