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Pachacha [2.7K]
3 years ago
15

What is the greatest common factor for the two expressions? 15³ and 12²​

Mathematics
1 answer:
den301095 [7]3 years ago
4 0

Answer:

Your answer would be 9.

Step-by-step explanation:

12*12=144

15*15*15=3375

The factors of 144 are: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, 144

The factors of 3375 are: 1, 3, 5, 9, 15, 25, 27, 45, 75, 125, 135, 225, 375, 675, 1125, 3375

So the greatest common factor would be 9 since is the largest number that is the same for both of the numbers.

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What percenr of 60 is 15
gregori [183]

Answer:

9%

Step-by-step explanation:15% of 60 is 9%

6 0
4 years ago
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Please help me with this on the image
Sedbober [7]

Answer:

we will then have to also multiply the y with three so the answer is B and that's ( ×3)

3 0
3 years ago
A ferris wheel is drawn on a coordinate plane so that the first car is located at the point ​(0​,40​). What are the coordinates
natulia [17]

Answer:

(40,0)

Step-by-step explanation:

A rotation of 270 degrees° counterclockwise about the​ origin has the rule

(x,y)\rightarrow (y,-x)

A ferris wheel is drawn on a coordinate plane so that the first car is located at the point ​(0​,40​).

According to the given rule, the image point after a rotation of 270 degrees° counterclockwise about the​ origin have the coordinates (40,0) (see attached diagram for details).

4 0
3 years ago
The senior class at High School A and High School B is planning seperate trips to the local museum. The senior class at High Sch
tatiyna

Answer:

Number of students van can carry = 11

Number of students bus can carry = 41

Step-by-step explanation:

Given the following :

HIGH SCHOOL A:

Number of students = 184

Number of vans(v) = 13

Number of buses(b) = 1

Mathematically,

13v + 1b = 184 - - - - (1)

HIGH SCHOOL B:

Number of students = 520

Number of vans(v) = 10

Number of buses(b) = 10

Mathematically,

10v + 10b = 520 - - - - (2)

Multiply (1) by 10 and (2) by 1

130v + 10b = 1840 - - - (3)

10v + 10b = 520 - - - (4)

Subtract (4) from (3)

120v = 1320

v = 11

Substitute v = 11 into (1)

13(11) + 1b = 184

143 + b = 184

b = 184 - 143

b = 41

Number of students van can carry = 11

Number of students bus can carry = 41

6 0
3 years ago
In a lottery, 5 numbers are drawn (without replacement) out of 90 (the numbers are 1 through 90).Find the probability that the n
vekshin1

Answer:

The probability that the number 7 is one of the numbers drawn is 1/18 or 0.0556.

Step-by-step explanation:

We have on number (7) in 90 possible numbers. There are 5 draws, without replacent.

The number 7 can be drawn in the first, second, third, fourth or fifth draw.

The probability of being picked in the first draw is:

P=\frac{1}{90}

The probability of being picked in the second draw is:

P=\frac{89}{90}*\frac{1}{89}=\frac{1}{90}

Note: in this case, is the probability of not being picked in the first draw and picked in the second, with one number less (already picked).

The probability of being picked in the third draw is:

P=\frac{89}{90}\frac{88}{89} \frac{1}{88}=\frac{1}{90}

The probability is the same for each draw. This can also have been realized by the fact that if the 7 is picked, in any draw, the replacement doesn't matter anymore.

The chances are the sum of the previous ones:

P=\frac{1}{90}+ \frac{1}{90}+ \frac{1}{90}+ \frac{1}{90}+ \frac{1}{90}=\frac{5}{90} =\frac{1}{18} =0.0556

5 0
3 years ago
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