Question

Find the distance between j(-3,4) and k(2,-4)

Answer 1

Answer:

$d=\sqrt{89}$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Simply plug in your 2 coordinates into the distance formula to find distance d:

$d=\sqrt{(2-(-3))^2+(-4-4)^2}$

$d=\sqrt{(2+3)^2+(-8)^2}$

$d=\sqrt{(5)^2+64}$

$d=\sqrt{25+64}$

$d=\sqrt{89}$