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3 years ago

Answer this now please :)

Mathematics

1 answer:

natta225 [31]3 years ago

4 0

9514 1404 393

Answer:

E. 384 cu ft

Step-by-step explanation:

The sum of length and width is half the perimeter, so the width is ...

(40/2) -12 = 8 . . . feet

The depth is half that, so is 8/2 = 4 feet.

The volume is ...

V = LWH = (12 ft)(8 ft)(4 ft) = 384 ft³

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88 Is 20 percent of what number?

ValentinkaMS [17]

Answer:

440

Step-by-step explanation:

You can write the problem statement in math terms as ...

88 = 0.20 × (what number)

To solve this, divide by the coefficient of the variable, 0.20.

88/0.20 = (what number)

440 = (what number)

The number you're looking for is 440.

_____

Of course you know that 20% = 20/100 = 0.20.

(% is a shorthand way to write /100.)

5 0

3 years ago

Please help. Find the area of the shaded polygons

ololo11 [35]

Answer:

A) yellow = 4.5

B) pink = 8

C) orange =9

Step-by-step explanation:

A) yellow = 12-2-1-4.5=4.5

B) pink = 7 whole plus 2 half equals 8

C) orange = 16-1-1.5-1.5-3=9

5 0

3 years ago

DO NOT SEND ME LINKS OR PDFS I WILL REPORT ANSWER CORRECTLY TO GET BRAINLIEST

bija089 [108]

Answer:

713

Step-by-step explanation:

Multiply 1,450 by 4.5 to get about 6,500 ants. Multiply 159 x 4.5 to get about 713. Hope this helps! Can you pls mark brainliest!

4 0

3 years ago

Read 2 more answers

the sequence {a_n} is defined by a_1= 1 and a_(n+1) = 1/2( a_n+ (4/a_n) ) for >=1. Assuming that {a_n} converges, find its li

katen-ka-za [31]

$a_{n+1}=\dfrac{a_n+\frac4{a_n}}2$

Assuming convergence of the sequence, we have $a_n\to L$ for some limit $L$ as $n\to\infty$ . This also means $a_{n+1}\to L$ . So in the above equation, we can substitute and solve for $L$ :

$L=\dfrac{L+\frac4L}2$

$\implies2L^2=L^2+4$

$\implies L^2=4\implies L=\pm2$

The limit can only be one of these values; otherwise, the sequence would be divergent. To decide which one is correct, we can observe that the sequence is strictly positive. So $L=2$ .

4 0

3 years ago

Find the upper 20%of the weight?

meriva

Answer:

The upper 20% of the weighs are weights of at least X, which is $X = 0.84\sigma + \mu$ , in which $\sigma$ is the standard deviation of all weights and $\mu$ is the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

$Z = \frac{X - \mu}{\sigma}$

$0.84 = \frac{X - \mu}{\sigma}$

$X = 0.84\sigma + \mu$

The upper 20% of the weighs are weights of at least X, which is $X = 0.84\sigma + \mu$ , in which $\sigma$ is the standard deviation of all weights and $\mu$ is the mean.

6 0

3 years ago