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ollegr [7]
3 years ago
15

the sequence {a_n} is defined by a_1= 1 and a_(n+1) = 1/2( a_n+ (4/a_n) ) for >=1. Assuming that {a_n} converges, find its li

mit.
Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0

a_{n+1}=\dfrac{a_n+\frac4{a_n}}2

Assuming convergence of the sequence, we have a_n\to L for some limit L as n\to\infty. This also means a_{n+1}\to L. So in the above equation, we can substitute and solve for L:

L=\dfrac{L+\frac4L}2

\implies2L^2=L^2+4

\implies L^2=4\implies L=\pm2

The limit can only be one of these values; otherwise, the sequence would be divergent. To decide which one is correct, we can observe that the sequence is strictly positive. So L=2.

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