Answer:
C
Step-by-step explanation:
plug in the points for the equation on C and you'll get see that it fits
To write the given quadratic equation to its vertex form, we first form a perfect square.
x² - 2x + 5 = 0
Transpose the constant to other side of the equation,
x² - 2x = -5
Complete the square in the left side of the equation,
x² - 2x + (-2/1(2))² = -5 + (-2/1(2))²
Performed the operation,
x² - 2x + 1 = -5 + 1
Factor the left side of the equation,
(x - 1)² = -4
Thus, the vertex form of the equation is,
<em> (x-1)² + 4 = 0</em>
Answer:
The working is done in the image attached.
Answer:
y = 28
Step-by-step explanation:
y = mx + b
plug in values
y = (6)(3) + (10)
multiply
y = 18 + (10)
add
y = 28
