Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:

Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Answer:
CA=17
Step-by-step explanation:
From given picture we see that A and C are the mid points of sides QR and QS respectively.
We know that line joining mid points of the two sides of triangle is always half of the length of the third side.
So that means:
2*CA=SR
2(3x-1)=5x+4
6x-2=5x+4
6x-5x=4+2
x=6
plug value of x into CA=3x-1
CA=3*6-1=18-1=17
Hence final answer is CA=17
Answer
v=-35
explanation
add -4 and -31 to get v which is -35
Answer:
50
Step-by-step explanation:
code in parm so the angle o is equal to e
that is a property of the parm
Answer:
62/x
Step-by-step explanation: