The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
5b - 5a
Step-by-step explanation:
b(5 - a) = 5b - ab
- a(b - 5) = - ab + 5a
Subtracting gives
5b - ab - (- ab + 5a) ← distribute parenthesis by - 1
= 5b - ab + ab - 5a ← collect like terms
= 5b - 5a
Answer:
Step-by-step explanation:
Answer:
The = sign
Step-by-step explanation:
1 11/20 = 31/20 = 1.55 and 1.55 =1.55
Answer:
x = 62
Step-by-step explanation:
x and 118 form a linear pair (added up, they both equal 180 degrees)
So, 180-118 = 62 which is the measurement of x
